Answer:
It will take the boulder approximately 4.28 seconds to hit the road
Step-by-step explanation:
The given height of the cliff from which the boulder falls, h = 90 feet
The equation that can be used to find the time it takes the boulder to fall is h = u·t + (1/2)·g·t²
Where;
h = The height of the cliff = 90 ft.
u = The initial velocity of the boulder = 0 m/s (The boulder is assumed to be at rest when it falls)
g - The acceleration due to gravity ≈ 9.81 m/s²
t = How long it will take for the boulder to hit the road below
Plugging in the values gives;
90 = 0 × t + (1/2)×9.81×t² = 4.905·t²
∴ t = √(90/4.905) ≈ 4.28
The time it takes the boulder to hit the road, t ≈ 4.28 seconds.
Answer:
108
Step-by-step explanation:
Limit as x approaches 9 of x^2 -81/sqrt of x - 3
First substitute x into the expression
= 9²-81/√9 - 3
= 81-81/3-3
= 0/0 (indeterminate)
Apply l'hospital rule
= lim x -> 9 d/dx(x²-81)/√x - 3
= lim x -> 9 2x/1/2√x
Substitute x = 9
= 2(9)/1/2√9
=18/1/(2(3)
=18 × 6/1
= 108
Hence the limit of the function is 108
If angle ec is a bisector then angles Bec and ced are the same making them both 4x+1. we know a line segment equals 180°. so if we take the 11x-12 and add it to 2(4x+1) we end up with 19x-10=180. you add 10 to both sides and get 19x=190 then you divide by both sides. you'll end up with x=10. you plug In the 10 with aeb and aec and add them together to get 139°. if you're looking for the equation, it's 15x-11.
