'One third' as a decimal is 1 ÷ 3 = 0.333333..... ⇒ The decimal is recurring
'One fifth' as decimal is 1 ÷ 5 = 0.2 ⇒ The decimal terminates at the tenth value
'One seventh' as decimal 1 ÷ 7 = 0.142857142857.... ⇒ The decimal is recurring for every digit between 1 and 7
'One ninth' as decimal 1 ÷ 9 = 0.111111.... ⇒ The decimal is recurring
Answer: one fifth
I think the answere is $67
B is the correct answer for your question I do believe, I hope that helped you. If not I am sorry, I tried to answer fast for you.
To find the distance between the points given in the figure of the problem above, you must apply the formula for calculate the distace between two points, which is shown below:
d=√[(x2-x1)^2+(y2-y1)^2]
When you substitute the values, you obtain:
d=√[(x2-x1)^2+(y2-y1)^2]
d=√[(-1-2)^2+(-5-5)^2]
d=10.4
The answer is:10.4
Answer is on the attachment. Brainlist pls.
Step-by-step explanation:
