Answer:
Step-by-step explanation:
82.1 = 82 1/10 (thats 82 and 1/10) or 821/10 (if you dont want a mixed number)
7.3 = 7 3/10 or 73/10
9.3 = 9 3/10 or 93/10
if there is 1 number to the right of the decimal, put that number over 10....not the whole number, just the number to the right of the decimal. Leave the number to the left of the decimal alone.
if there were 2 numbers to the right of the decimal, then put those two numbers over 100.
example :
3.43 = 3 43/100
2.76 = 2 76/100
if there were 3 numbers to the right of the decimal, put those 3 numbers over 1000
example :
2.347 = 2 347/1000
3.679 = 3 679/1000
you understand ?
The angles remain the same. If you equally increase the lengths of the sides, the interior and exterior angles will not change. Both of them are similar to the original sign.
Answer:
Options (1), (2), (3) and (7)
Step-by-step explanation:
Given expression is ![\frac{\sqrt[3]{8^{\frac{1}{3}}\times 3} }{3\times2^{\frac{1}{9}}}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Csqrt%5B3%5D%7B8%5E%7B%5Cfrac%7B1%7D%7B3%7D%7D%5Ctimes%203%7D%20%7D%7B3%5Ctimes2%5E%7B%5Cfrac%7B1%7D%7B9%7D%7D%7D)
.
Now we will solve this expression with the help of law of exponents.
![\frac{\sqrt[3]{8^{\frac{1}{3}}\times 3} }{3\times2^{\frac{1}{9}}}=\frac{\sqrt[3]{(2^3)^{\frac{1}{3}}\times 3} }{3\times2^{\frac{1}{9}}}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Csqrt%5B3%5D%7B8%5E%7B%5Cfrac%7B1%7D%7B3%7D%7D%5Ctimes%203%7D%20%7D%7B3%5Ctimes2%5E%7B%5Cfrac%7B1%7D%7B9%7D%7D%7D%3D%5Cfrac%7B%5Csqrt%5B3%5D%7B%282%5E3%29%5E%7B%5Cfrac%7B1%7D%7B3%7D%7D%5Ctimes%203%7D%20%7D%7B3%5Ctimes2%5E%7B%5Cfrac%7B1%7D%7B9%7D%7D%7D)
![=\frac{\sqrt[3]{2\times 3} }{3\times2^{\frac{1}{9}}}](https://tex.z-dn.net/?f=%3D%5Cfrac%7B%5Csqrt%5B3%5D%7B2%5Ctimes%203%7D%20%7D%7B3%5Ctimes2%5E%7B%5Cfrac%7B1%7D%7B9%7D%7D%7D)
[Option 2]
![2^{\frac{2}{9}}\times 3^{-\frac{2}{3} }=(\sqrt[9]{2})^2\times (\sqrt[3]{\frac{1}{3} } )^2](https://tex.z-dn.net/?f=2%5E%7B%5Cfrac%7B2%7D%7B9%7D%7D%5Ctimes%203%5E%7B-%5Cfrac%7B2%7D%7B3%7D%20%7D%3D%28%5Csqrt%5B9%5D%7B2%7D%29%5E2%5Ctimes%20%28%5Csqrt%5B3%5D%7B%5Cfrac%7B1%7D%7B3%7D%20%7D%20%29%5E2)
[Option 1]
![=\sqrt[9]{4}\times \sqrt[3]{\frac{1}{9} }](https://tex.z-dn.net/?f=%3D%5Csqrt%5B9%5D%7B4%7D%5Ctimes%20%5Csqrt%5B3%5D%7B%5Cfrac%7B1%7D%7B9%7D%20%7D)
[Option 3]
![=\sqrt[9]{2^2}\times \sqrt[3]{3^{-2}}](https://tex.z-dn.net/?f=%3D%5Csqrt%5B9%5D%7B2%5E2%7D%5Ctimes%20%5Csqrt%5B3%5D%7B3%5E%7B-2%7D%7D)
[Option 7]
Therefore, Options (1), (2), (3) and (7) are the correct options.
Answer:
A. (55 x 5) - (40 x 5)
Step-by-step explanation:
You are solving how much miles (further along) would the second car be after 5 hours.
The first car averages 40 miles per hour. 5 hours later, it will have averaged about 200 miles in 5 hours (40 x 5 = 200).
The second car averages 55 miles per hour. 5 hours later, it will have averaged about 275 miles in 5 hours (55 x 5 = 275)
Subtract: 275 - 200 = 75
The second car would have averaged 75 more miles than the first car.
~
Answer:
7.5
Step-by-step explanation:
The relation between time, speed, and distance is ...
time = distance/speed
If distance is "1 round trip", then the time going is ...
going = 0.5/(10 mi/h) . . . . for 1/2 round trip
and the time coming is ...
coming = 0.5/(6 mi/h)
Then the average speed for the full round trip is ...
speed = distance/time
average speed = 1/(going + coming) = 1/(0.5/10 +0.5/6) mi/h
= 1/((3+5)/60) mi/h
= 60/8 mi/h = 7.5 mi/h
Jack's average speed for the round trip was 7.5 mph.
