Answer:
<u><em>I got x=2</em></u>
Step-by-step explanation:
<u><em>1. Simplify the quadratic equation into its standard form</em></u>
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<u><em>Ax^2 +Bxc=0</em></u>
<u><em>Simplify the equation by subtracting everything to the right of the equal sign from both sides of the equation and combining like terms.</em></u>
<u><em>x^2-12x+0=-20</em></u>
<u><em>x^2-12x+0+20=0</em></u>
<u><em>x^2-12x+20=0</em></u>
<u><em>The Quadratic formula provides the solution for Ax^2 +Bxc=0, in which A, B, and C are numbers (or coefficients), as follows:</em></u>
<u><em>The coefficients of our equation, x^2-12x+20=0, are:</em></u>
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<u><em>A = 1</em></u>
<u><em>B = -12</em></u>
<u><em>C = 20</em></u>
<u><em>Simplify 64 by finding its prime factors.</em></u>
<u><em>We first calculate the expressions inside the parentheses from left to right and from inner to outer.</em></u>
<u><em>x=12-8/2</em></u>
<u><em>x=4/2</em></u>
<u><em>x=2 </em></u>