Using a binomial distribution considering there's a 30% chance it will rain on any of the three days:
<span>The probability of it raining on 0 days is (1)(0.7)(0.7)(0.7) = 34.3%. </span>
<span>The probability of it raining on 1 day is (3)(0.3)(0.7)(0.7) = 44.1%. </span>
<span>The probability of it raining on 2 days is (3)(0.3)(0.3)(0.7) = 18.9%. </span>
<span>The probability of it raining on 3 days is (1)(0.3)(0.3)(0.3) = 2.7%. </span>
<span>There's a 65.7% chance that it will rain at least once over the three-day period.</span>
Answer:
KL = 10
Step-by-step explanation:
JK + KL = JL
2x – 2 + x – 9 = 2x + 8
Combine like terms
3x -11 = 2x+8
Subtract 2x from each side
3x-2x -11 = 2x+8-2x
x-11 = 8
Add 11 to each side
x-11+11 = 8+11
x = 19
KL = x – 9
= 19-9
= 10
Answer:
17 + 2i
Step-by-step explanation:
Given
(2 - 3i) + 5i(1 - 3i) ← distribute both parenthesis
= 2 - 3i + 5i - 15i² [ i² = - 1 ]
= 2 + 2i + 15
= 17 + 2i ← in standard form