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bija089 [108]
3 years ago
14

Question

Mathematics
1 answer:
Luden [163]3 years ago
3 0

Answer:

Step-by-step explanation:

2 units squared.

Explanation:

You can go about this in two ways: Algebra and Integrals.

Algebra

y = 2x-6 is linear, thus if we take the value over the x interval [2,4] we can use geometry to calculate the area.

graph{2x-6 [-2.27, 7.73, -2.18, 2.82]}

You can see two triangles in the graph (you could also find this algebraically). Thus, you can calculate the area.

=

2

⋅

(

1

2

⋅

b

⋅

h

)

=

2

⋅

(

1

2

⋅

1

⋅

2

)

=

2

square units

Integrals

An integral gives the area under the curve. Remember though that if a function goes below the X axis, the integral is negative Thus you have to do two separate integrals based on the X intercept.

finding the X intercept (that is where y = 0)

2

x

−

6

=

0

x

=

3

when

y

=

0

When

x

<

3

, then y is negative. Thus, we have to find the negative integral from 2 to 3 and the positive integral from 3 to 4

=

−

∫

3

2

2

x

−

6

d

x

+

∫

4

3

2

x

−

6

d

x

=

−

[

x

2

−

6

x

]

3

2

+

[

x

2

−

6

x

]

4

3

=

−

[

9

−

18

−

4

+

12

]

+

[

16

−

24

−

9

+

18

]

=

−

[

−

1

]

+

[

1

]

=

2

units squared. And Tada, that is the same as the other answer!

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What is (9 x2/3) x2/3
lutik1710 [3]

Answer:

4

Step-by-step explanation:

First you have to follow pemdas, which says you have to follow this order:

Parentheses first, exponents second, multiply, divide, add, and then subtract. Always follow from left to right. First solve inside the parentheses.

9x2/3=6 and then multiply the product by 2/3 {6x2/3=4}

4 0
2 years ago
Find the arc length of the given curve between the specified points. x = y^4/16 + 1/2y^2 from (9/16), 1) to (9/8, 2).
lutik1710 [3]

Answer:

The arc length is \dfrac{21}{16}

Step-by-step explanation:

Given that,

The given curve between the specified points is

x=\dfrac{y^4}{16}+\dfrac{1}{2y^2}

The points from (\dfrac{9}{16},1) to (\dfrac{9}{8},2)

We need to calculate the value of \dfrac{dx}{dy}

Using given equation

x=\dfrac{y^4}{16}+\dfrac{1}{2y^2}

On differentiating w.r.to y

\dfrac{dx}{dy}=\dfrac{d}{dy}(\dfrac{y^2}{16}+\dfrac{1}{2y^2})

\dfrac{dx}{dy}=\dfrac{1}{16}\dfrac{d}{dy}(y^4)+\dfrac{1}{2}\dfrac{d}{dy}(y^{-2})

\dfrac{dx}{dy}=\dfrac{1}{16}(4y^{3})+\dfrac{1}{2}(-2y^{-3})

\dfrac{dx}{dy}=\dfrac{y^3}{4}-y^{-3}

We need to calculate the arc length

Using formula of arc length

L=\int_{a}^{b}{\sqrt{1+(\dfrac{dx}{dy})^2}dy}

Put the value into the formula

L=\int_{1}^{2}{\sqrt{1+(\dfrac{y^3}{4}-y^{-3})^2}dy}

L=\int_{1}^{2}{\sqrt{1+(\dfrac{y^3}{4})^2+(y^{-3})^2-2\times\dfrac{y^3}{4}\times y^{-3}}dy}

L=\int_{1}^{2}{\sqrt{1+(\dfrac{y^3}{4})^2+(y^{-3})^2-\dfrac{1}{2}}dy}

L=\int_{1}^{2}{\sqrt{(\dfrac{y^3}{4})^2+(y^{-3})^2+\dfrac{1}{2}}dy}

L=\int_{1}^{2}{\sqrt{(\dfrac{y^3}{4}+y^{-3})^2}dy}

L= \int_{1}^{2}{(\dfrac{y^3}{4}+y^{-3})dy}

L=(\dfrac{y^{3+1}}{4\times4}+\dfrac{y^{-3+1}}{-3+1})_{1}^{2}

L=(\dfrac{y^4}{16}+\dfrac{y^{-2}}{-2})_{1}^{2}

Put the limits

L=(\dfrac{2^4}{16}+\dfrac{2^{-2}}{-2}-\dfrac{1^4}{16}-\dfrac{(1)^{-2}}{-2})

L=\dfrac{21}{16}

Hence, The arc length is \dfrac{21}{16}

6 0
3 years ago
The local park has 4 bike racks. Each bike rack can hold 15 bikes. There are 16 bikes in the bike racks. What expression shows t
Step2247 [10]
44 that's a tricky question at first i thought it was -1 lol
5 0
3 years ago
Find a formula for the number of patrons as a function of profit.
Solnce55 [7]
Here is my answer. Let just give assumptions. For example,the relationship is linear.Therefore the slope, "m," is the same throughout.
Let us make patrons the independent variable, the two points are: (1314, 11333) and (1544, 13518).
m = (13518-11333)/(1544-1314)
m = 9.5
 
profit = 9.5 patrons (you pick the variable names)
For 1 more patron substitute 1:
profit = 9.5 (1)
profit = 9.5
 
Isolate "patrons" and you get the function based on profit:
patrons = profit/9.5
 
The break even point is for 0 < profit.
0 < profit = 9.5 patrons
0 < 9.5 patrons
0 < patron
5 0
3 years ago
Write an equation in point slope form that passes through the given point and has the given slope.
stich3 [128]
Y+2=4(x-5) pretty sure
7 0
2 years ago
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