If AB is tangent to the circle, then angle ABO is right angle and triangle AOB is special $30^{\circ}-60^{\circ}-90^{\circ}$ triangle. In this triangle, the leg that is opposite to the angle of 30° is half of the hypotenuse. Thus,

$AO=2BO=2\cdot 12=24\ cm.$

By the Pythagorean theorem,

$AB^2=AO^2-BO^2,\\ \\AB^2=24^2-12^2,\\ \\AB^2=576-144=432,\\ \\AB=12\sqrt{3}\ cm.$

6 0

3 years ago

A line has a slope of -13. There is a second line that passes through points (-7,-5) and (6,-4) . Would these lines be parallel

Elza [17]

<h3>Answer: The lines are perpendicular</h3>

=================================================

Work Shown:

Use the slope formula to find the slope of the line through the two given points.

m = (y2 - y1)/(x2 - x1)

m = (-4 - (-5))/(6 - (-7))

m = (-4 + 5)/(6 + 7)

m = 1/13

The slope of the line through the two given points is 1/13.

This is not equal to -13, which was the slope of the first line, so the two lines are not parallel.

However, the two lines are perpendicular because multiplying the two slope values leads to -1

(slope1)*(slope2) = (-13)*(1/13) = -1

note: It might help to think of -13 as -13/1 to help multiply the fractions.

3 0

3 years ago

Simplify the expression -2b-6+3b-2

netineya [11]

The expression can be simplified as:

b-8

5 0

3 years ago