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Novosadov [1.4K]
3 years ago
5

The model represents the factorization of 2x2+5x+3.

Mathematics
1 answer:
Lapatulllka [165]3 years ago
3 0

Answer:

(2x+3)(x+1)

Step-by-step explanation:

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According to the Tristate Transportation Authority, making certain improvements to the main commuter rail line would increase ri
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Answer:

Options A and B are true

(A) Before the authority increases tolls on any of the area bridges, it is required by law to hold public hearings at which objections to the proposed increase can be raised.

B. (B) Whenever bridge tolls are increased, the authority must pay a private contractor to adjust the automated toll-collecting machines.

Step-by-step explanation:

A. In a developed society, it's imperative for the authority to hold public hearings with stake holders to air their views before the tolls are increased, this would enable the authority to carry out proper assessment to know both the positive and negative impact of increasing the toll.

B. Increasing the tolls implies that there must be adjustment in the automated tolling machines and this would incur cost on the authority, this contract would be executed by private contractors.

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4 years ago
Exploring Area of a Regular Polygon
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Answer:

Step-by-step explanation:

5 0
4 years ago
Evaluate 2/5 log 32 + (log 9 )/log 3) Please Show Working?
sattari [20]

Simplify the expression

exact form:

log(4)+log(9)/log(3)

Decimal Form:

2.60205999 . . .

Hope this helps! :)

~Zane

6 0
3 years ago
What’s the value of x?
Radda [10]

Answer:

the answer is A.)23

Step-by-step explanation:

3 0
4 years ago
Please help me I am having a hard time with this activity
zysi [14]

Answer:

Step-by-step explanation:

b.

\frac{a^2+6a+9}{a^2-9} *\frac{3a-9}{a+3} \\=\frac{a^2+2*a*3+3^2}{a^2-3^2} *\frac{3(a-3)}{a+3} \\=\frac{(a+3)^2}{(a+3)(a-3)} *\frac{3(a-3)}{a+3} \\=\frac{3(a+3)^2}{(a+3)^2} \\=3

d.

\frac{3x^2-6x}{3x+1} *\frac{x+3x^2}{x^2-4x+4} \\=\frac{3x(x-2)}{3x+1} *\frac{x(1+3x)}{x^2-2x-2x+4} \\=\frac{3x(x-2)}{3x+1} *\frac{x(1+3x)}{x(x-2)-2(x-2)} \\=\frac{3x(x-2)}{3x+1} *\frac{x(1+3x)}{(x-2)(x-2) } \\=\frac{3x^2}{x-2)}

e.

\frac{2x^2-10x+12}{x^2-4} *\frac{2+x}{3-x} \\=\frac{2[x^2-5x+6]}{x^2-2^2} *\frac{2+x}{-(-3+x)} \\=\frac{2[x^2-2x-3x+6]}{(x+2)(x-2)} *\frac{x+2}{-(x-3)} \\=\frac{2[x(x-2)-3(x-2)]}{(x+2)(x-2)} *\frac{x+2}{-(x-3)} \\=\frac{2(x-2)(x-3)}{(x+2)(x-2)} *\frac{x+2}{-(x-3)} \\=\frac{2}{-1} \\=-2

k.

\frac{6x^2-11x-10}{6x^2-5x-6} *\frac{6-4x}{25-20x+4x^2} \\=\frac{6x^2-15x+4x-10}{6x^2-9x+4x-6} *\frac{-4x+6}{4x^2-10x-10x+25} \\=\frac{3x(2x-5)+2(2x-5)}{3x(2x-3)+2(2x-3) } *\frac{-2(2x-3)}{2x(2x-5)-5(2x-5)} \\=\frac{(2x-5)(3x+2)}{(2x-3)(3x+2)} *\frac{-2(2x-3)}{(2x-5)(2x-5)} \\=\frac{-2}{2x-5}

7 0
3 years ago
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