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Alla [95]
3 years ago
5

Asap asap plz help i will mark brainliest

Mathematics
1 answer:
Kay [80]3 years ago
7 0

Step-by-step explanation:

First we need to solve for z

Each side has a length:

VX=3z

VW=2z+2

WX=z+3

P=VW+VX+WX

P=(2z+2)+3z+(z+3)

P=6z+5

59=6z+5

54=6z

z=9

So the length of line WX=z+3

WX=12

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<u>ANSWER:  </u>

The vertex of given equation  y=-x^{2}+12 x-4 is (6, 32).

<u>SOLUTION: </u>

Given, quadratic equation is  y=-x^{2}+12 x-4

Above equation is a parabola and we need to find the vertex of that parabola.  We know that, general form of the parabola is  y=a(x-h)^{2}+k

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