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il63 [147K]
3 years ago
8

Match each function with the expression representing Its Inverse function.

Mathematics
1 answer:
USPshnik [31]3 years ago
7 0

Answer:

Step-by-step explanation:

1). g(x) = -0.5x

   Equation form of the given function is,

   y = -0.5x

 Interchange x and y,

  x = -0.5y

  Solve for y,

  y = -\frac{x}{0.5}

  y = -2x

  Inverse function will be,

  g^{-1}x=-2x

2). h(x) = 4x

   Equation form of the function will be,

   y = 4x

   Interchange x and y,

   x = 4y

   Solve for y,

   y = \frac{x}{4}

   Inverse function will be,

   h^{-1}(x)=0.25x

3). y = x - 4

    Interchange x and y,

    x = y - 4

    Solve for y,

    y = x + 4

    Therefore, inverse of the linear equation is,

    y = x + 4

4). f(x) = \frac{x}{2}

    Equation form of the function will be,

    y = \frac{x}{2}= x

     Interchange x and y,  

     x = \frac{y}{2}

    Solve for y,

     y = 2x

     Therefore, inverse function will be,

     f^{-1}(x)=2x

5). k(x) = x

     Equation form of the function will be,

     y = x

     Interchange x and y,

     x = y

     Solve for y,

     y = x

     Inverse of the function 'f' will be,

     k^{-1}(x) =x

6). p(x) = x + 4

     Equation form of the function will be,

     y = x + 4

     Interchange x and y,

     x = y + 4

     Solve for y,

     y = x - 4

     Inverse of the function 'p' will be,

     p^{-1}(x)=x - 4

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A) What is the equation of the line that passes through the given pair points in slope-intercept form?
lesya [120]

A)

The slope-intercept form:

y=mx+b

m - slope

b - y-intercept

The formula of a slope:

m=\dfrac{y_2-y_1}{x_2-x_1}

We have the points (2, 5.1) and (-1, -0.5). Substitute:

m=\dfrac{-0.5-5.1}{-1-2}=\dfrac{-5.6}{-3}=\dfrac{5.6}{3}=\dfrac{56}{30}=\dfrac{28}{15}

Therefore we have:

y=\dfrac{28}{15}x+b

Put the coordinates of the point (-1, -0.5) ot the equation:

-0.5=\dfrac{28}{15}(-1)+b

-0.5=-\dfrac{28}{15}+b     <em>multiply both sides by 2</em>

-1=-\dfrac{56}{15}+2b       <em>add \dfrac{56}{15} to both sides</em>

\dfrac{41}{15}=2b            <em>divide both sides by 2</em>

b=\dfrac{41}{30}

Answer: \boxed{y=\dfrac{28}{15}x+\dfrac{41}{30}}

-------------------------------------------------------------------------

B)

We have the points (-2, 3) and (3, -4).

Calculate the slope:

m=\dfrac{-4-3}{3-(-2)}=\dfrac{-7}{5}=-\dfrac{7}{5}

Therefore we have:

y=-\dfrac{7}{5}x+b

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\dfrac{1}{5}=b\to b=\dfrac{1}{5}

Answer: \boxed{y=-\dfrac{7}{5}x+\dfrac{1}{5}}

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