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aev [14]
4 years ago
7

A) What is the equation of the line that passes through the given pair points in slope-intercept form?

Mathematics
1 answer:
lesya [120]4 years ago
7 0

A)

The slope-intercept form:

y=mx+b

m - slope

b - y-intercept

The formula of a slope:

m=\dfrac{y_2-y_1}{x_2-x_1}

We have the points (2, 5.1) and (-1, -0.5). Substitute:

m=\dfrac{-0.5-5.1}{-1-2}=\dfrac{-5.6}{-3}=\dfrac{5.6}{3}=\dfrac{56}{30}=\dfrac{28}{15}

Therefore we have:

y=\dfrac{28}{15}x+b

Put the coordinates of the point (-1, -0.5) ot the equation:

-0.5=\dfrac{28}{15}(-1)+b

-0.5=-\dfrac{28}{15}+b     <em>multiply both sides by 2</em>

-1=-\dfrac{56}{15}+2b       <em>add \dfrac{56}{15} to both sides</em>

\dfrac{41}{15}=2b            <em>divide both sides by 2</em>

b=\dfrac{41}{30}

Answer: \boxed{y=\dfrac{28}{15}x+\dfrac{41}{30}}

-------------------------------------------------------------------------

B)

We have the points (-2, 3) and (3, -4).

Calculate the slope:

m=\dfrac{-4-3}{3-(-2)}=\dfrac{-7}{5}=-\dfrac{7}{5}

Therefore we have:

y=-\dfrac{7}{5}x+b

Put the coordinates of the point (-2, 3) to the equation of a line:

3=-\dfrac{7}{5}(-2)+b

\dfrac{15}{5}=\dfrac{14}{5}+b              <em>subtract \dfrac{14}{5} from both sides</em>

\dfrac{1}{5}=b\to b=\dfrac{1}{5}

Answer: \boxed{y=-\dfrac{7}{5}x+\dfrac{1}{5}}

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