Answer:
<h2>There are 13 quarters, 5 nickels and 20 dimes.</h2>
Step-by-step explanation:
Givens
- Max has $5.50.
- He has eight more quarters than he does nickels.
- He had four times as many dimes as he has nickels.
From these statements, we can deduce algebraical expressions to solve the problem. Let's call 
quarters, 
nickels and 
dimes.
(8 more quarters than nickels)
(he has four times as many dimes as he has nickels).
(Max has a total of $5.50, one quartes is $0.25, one nickel is $0.05 and one dime is $0.10).
Let's replace the first two expressions into the third equation
There are 5 nickels.
Now, we use this value to find the number of quarters
There are 13 quarters.
Also, 
There are 20 dimes.
Therefore, there are 13 quarters, 5 nickels and 20 dimes.
9 years because if you do 4700 * 1.03= 4831 now do that 9 times you get 6,132.43
Answer: Check
12^10 × 12^(-2) = 12^(10 - 2) = 12^8
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Second option : ---
3^2 × 4^6 = 3^2 × 4^2 × 4^4 = 12^2 × 4^4
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Third option : ---
(12^8)^0 = 12^(8 × 0) = 12^0 = 1
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4th option : Check
12^10 / 12^2 = 12^10 × 12^(-2) = 12^(10 - 2)
= 12^8
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5th option : Check
2^8 × 6^8 = ( 2 × 6 )^8 = 12^8
Step-by-step explanation:
The answer is C. 50% because 50% of 5,000 is 2,500 and 2,500+5,000= 7,500
Answer:
divide both sides by 3
Step-by-step explanation:
so the answer should be x=3
