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Tanzania [10]
3 years ago
9

A clock shows 5:00. What time is it after the minute hand rotates 90 degrees?

Mathematics
2 answers:
kramer3 years ago
6 0
Each 90° rotation of the minute hand correspond to 15 minutes.
So will be 5.15 hs
masya89 [10]3 years ago
5 0
5:15 Because Rotating 90 Degrees would be at the 3 so. 5:15

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Seven subtracted from the product of 5 and a number is at least 24
Dovator [93]

Answer:

5a-7=24

5a=24+7

a=31/5

Step-by-step explanation:

8 0
2 years ago
Eight less than four times a number is less than 56.What are the possible values of that number
Gemiola [76]
We have the next inequation
8-4x<56

-4x<56-8
-4x<48
-x<48/4
-x<12
x>-12

Solution: x>-12  or  (-12,+∞)
4 0
3 years ago
At the city museum, child admission is $5.30 and adult admission is $9.20 . On Monday, 166 tickets were sold for a total sales o
Sonbull [250]
C+a=166
a=166-c
5.3c+9.2a=1254.2
5.3c+9.2(166-c)=1254.2
5.3c+1527.2-9.2c=1254.2
5.3c-9.2c=1254.2-1527.2
-3.9c=-273
c=-273/-3.9
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Hope this helps!

3 0
3 years ago
Joanie watched 1 out of three of a movie in the morning
Archy [21]

Answer:

7/15

Step-by-step explanation:

Determine how much she has watched.

1/3 + 1/5 The common denominator of 3 and 5 is 15. Multiply each fraction by an amount that will make the denominator 15

1/3 = 1*5/(3*5) = 5 / 15

1/5 = 1*3 / (5*3) = 3/15

Now add the two fractions together.

5/15 + 3/15 = 8/15

What is left of the movie? The whole movie = 1 so that which is left is

1 - 8/15

15/15 - 8/15

7 / 15

She has just a bit under 1/2 to go.

8 0
3 years ago
How do I solve these problems? ln(x) = 5.6 + ln(7.5) and log(x) = 5.6 - log(7.5)
SOVA2 [1]

Use the rules of logarithms and the rules of exponents.

... ln(ab) = ln(a) + ln(b)

... e^ln(a) = a

... (a^b)·(a^c) = a^(b+c)

_____

1) Use the second rule and take the antilog.

... e^ln(x) = x = e^(5.6 + ln(7.5))

... x = (e^5.6)·(e^ln(7.5)) . . . . . . use the rule of exponents

... x = 7.5·e^5.6 . . . . . . . . . . . . use the second rule of logarithms

... x ≈ 2028.2 . . . . . . . . . . . . . use your calculator (could do this after the 1st step)

2) Similar to the previous problem, except base-10 logs are involved.

... x = 10^(5.6 -log(7.5)) . . . . . take the antilog. Could evaluate now.

... = (1/7.5)·10^5.6 . . . . . . . . . . of course, 10^(-log(7.5)) = 7.5^-1 = 1/7.5

... x ≈ 53,080.96

8 0
3 years ago
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