Answer:
Step-by-step explanation:
Given that:
<u>For PCC</u>
The sample size = 25
sample mean = 75
standard deviation = 17.50
<u>For ELAC</u>
The sample size = 20
Sample mean
Standard deviation = 14.40
Significance level = 0.05
The null hypothesis:
The alternative hypothesis;
Since the population standard deviation are synonymous pooled standard deviation; Then:
The test statistics can be computed as:
The p-value
= 0.0031
Decision Rule: To reject the null hypothesis if the p-value is less than the significance level
Conclusion: There is sufficient evidence to conclude that the mean amount spent by all PCC students is less than the mean amount spent by all ELAC students.