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alexdok [17]
3 years ago
5

Which function is the inverse of f(x) = –5x – 4?

Mathematics
2 answers:
UNO [17]3 years ago
6 0

Answer:

f^{-1}(x)=-\frac{1}{5}x-\frac{4}{5}

Step-by-step explanation:

we have

f(x)=-5x-4

Let

y=f(x)

y=-5x-4

Step 1

Exchange the variables x for y and y for x

x=-5y-4

Step 2

Isolate the variable y

x=-5y-4

5y=-x-4

y=-\frac{1}{5}x-\frac{4}{5}

Step 3

Let

f^{-1}(x)=y

f^{-1}(x)=-\frac{1}{5}x-\frac{4}{5}

ra1l [238]3 years ago
5 0
Just took the test. A is the right answer. 
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Archy [21]

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7 0
3 years ago
A) Write the sequence of natural numbers which are multiplied by 3 ?
Volgvan

Answer:

a) 3, 6, 9, 12, 15,...,3\cdot n, b) 4, 7, 10, 13, 16,...,3\cdot n +1, c) Both sequences are arithmetic.

Step-by-step explanation:

a) The sequence of natural numbers which are multiplied by 3 are represented by the function f(n) = 3\cdot n, n\in \mathbb{N}. Let see the first five elements of the sequence: 3, 6, 9, 12, 15,...

b) The sequence of natural numbers which are multiplied by 3 and added to 1 is represented by the function f(n) = 3\cdot n + 1, n\in \mathbb{N}. Let see the first five elements of the sequence: 4, 7, 10, 13, 16,...

c) Both sequences since differences between consecutive elements is constant. Let prove this statement:

(i) f(n) = 3\cdot n

\Delta f = f(n+1) -f(n)

\Delta f = 3\cdot (n+1) -3\cdot n

\Delta f = 3

(ii) f(n) = 3\cdot n +1

\Delta f = f(n+1)-f(n)

\Delta f = [3\cdot (n+1)+1]-(3\cdot n+1)

\Delta f = 3

Both sequences are arithmetic.

8 0
3 years ago
I need helpppp, I need to turn this in before class is over
svetoff [14.1K]

Answer:

.

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
To Rationalize the denominator of 5-√7/9-√14, you should multiply the expression by which fractions?
beks73 [17]

<u>Answer</u>

9+√14


<u>Explanation</u>

To Rationalize the denominator of 5-√7/9-√14.

To rationalize this we multiply both the denominator and denominator by the conjugate of the denominator.

The denominator is 9-√14 and its conjugate is (9+√14).

(5-√7)/(9-√14) = (5-√7)(9+√14)/(9-√14)(9+√14)

                        =  (5-√7)(9+√14)/(9²-14)

                       = (45 + 5√14 - 9√7 - √98)/(81-14)

                        =  (45 + 5√14 - 9√7 - √98)/67

                        = (45 + 5√14 - 9√7 - 7√2)67

This is the rationalized expression.  

The denominator is (9-√14) and its conjugate is (9+√14).

8 0
3 years ago
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Line Q??? You don't really have an image of it
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