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abruzzese [7]
3 years ago
12

Help help PLEASE i will love you for eternity, THATS IF I GET IT RIGHT

Mathematics
1 answer:
marysya [2.9K]3 years ago
6 0

Answer:

the first ones is the first one :)

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{(12*3)+6}-3^2 divided by (9-6)
Mrac [35]
33. 12*3=36 the u add 6 so it becomes 42. 3^2 is 9 so if u subtract 9 from 42 it becomes 33. 
6 0
3 years ago
Mary's math certificate is 10 inches tall and 13 inches wide. Mary wants to put the certificate
wlad13 [49]

Answer:

$219.70

Step-by-step explanation:

First, you need to find the area of the certificate, which you can do by multiplying 10*13, since it is a rectangle. 10*13 is 130. Then, multiply 130 by the price per inch, which is $1.69. 130*1.69=219.7, which in financial terms would amount to $219.70.

8 0
3 years ago
PLEAS3E CHECK MY ANSWER
IRINA_888 [86]
I'd say the correct answer is D bc it's talking about the SAS theorem, excuse me if I'm wrong tho.
4 0
4 years ago
Given: AE = 3, CE = 5 and ED is 4 less than EB find EB. Please give a step-by-step explanation. The best answer will receive bra
alisha [4.7K]

Answer:

EB = 10

Step-by-step explanation:

For this problem, you can use the power of a point, in the situation where two secants intersect in the interior of a circle. The formula is as follows:

CE * ED = AE * EB

(This is applied specifically to this problem)

We can substitute the values given,

5 * (x - 4) = 3 * x

simplify,

5x - 20 = 3x

and solve.

2x - 20 = 0

2x = 20

x = 10

Since the value of EB is x, EB = 10.

6 0
3 years ago
Please help me look at the picture
harina [27]

The answer is choice A.

We're told that the left and right walls of the cube (LMN and PQR) are parallel planes. Any line contained in one of those planes will not meet another line contained in another plane. With choice A, it's possible to have the front and back walls be non-parallel and still meet the initial conditions. If this is the case, then OS won't be paralle to NR. Similarly, LP won't be parallel to MQ.

8 0
3 years ago
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