The probability of selecting exactly one ace is its likelihood
The probability that a five-card poker hand contains exactly one ace is 29.95%
<h3>How to determine the probability?</h3>
There are 4 aces in a standard deck of 52 cards.
The probability of selecting an ace would be:
p = 4/52
Also, there are 48 non-ace cards in the standard deck
So, the probability of selecting a non-ace after an ace has been selected is:
p = 48/51
The probability of selecting a non-ace up to the fifth selection are:
- After two cards have been selected is: 47/50.
- After three cards have been selected is: 46/49.
- After four cards have been selected is: 45/48.
The required probability is then calculated as:
P(1 Ace) = n * (4/52) * (48/51) * (47/50) * (46/49) * (45/48)
Where n is the number of cards i.e. 5
So, we have:
P(1 Ace) = 5 * (4/52) * (48/51) * (47/50) * (46/49) * (45/48)
Evaluate
P(1 Ace) = 0.2995
Express as percentage
P(1 Ace) = 29.95%
Hence, the probability that a five-card poker hand contains exactly one ace is 29.95%
Read more about probability at:
brainly.com/question/25870256
Answer:
The answer is (D) ⇒ a = 11.71 , b = 15.56
Step-by-step explanation:
* In ΔABC
∵ m∠A = 45°
∵ m∠B = 110°
∴ m∠C = 180 - 45 - 110 = 25°
By using the sin Rule
∵ a/sin(A) = b/sin(B) = c/sin(C)
∵ c = 7
∴ a/sin(45) = b/sin(110) = 7/sin(25)
∴ a = (7 × sin(45)) ÷ sin(25) = 11.71
∴ b = (7 × sin(110)) ÷ sin(25) = 15.56
∴ The answer is (D)
You need to find the equation of y=Mx+b
Answer is y=-5/3x+5
Brainliest?
Answer:
338.4Step-by-step explanation:
If you do 80 percent of 188, its 150.4. Then, you add 150.4 to 188. thats 338.4
Answer:
15 inches
Step-by-step explanation:
12 inches = 1ft
12ft = 144 inches
144/9 = 16
20ft = 240 inches
240/16 = 15 inches
