In a pool of water filled to a depth of 10 ft, calculate the fluid force on one side of a 3 ft by 4 ft rectangular plate if it r ests vertically on its 4 ft edge at the bottom of the pool. Remember that water weighs 62.4 lb/ft3
1 answer:
9514 1404 393
Answer:
6,364.8 lb
Step-by-step explanation:
The centroid of the plate is its center, so is 1.5 ft above the bottom of the pool, or 8.5 ft below the surface. The area of the plate is (3 ft)(4 ft) = 12 ft². Then the fluid force is ...
(62.4 lb/ft³)(8.5 ft)(12 ft²) = 6,364.8 lb
You might be interested in
Answer:
Step-by-step explanation:
39²=1521
80²=6400
39²+80²=1521+6400=7921
87²=7569
7921≠7569
so it is not aright angled triangle.
Answer:
(A), 21, 22,and 26
Step-by-step explanation:
gakzbzkxvuxnsslvzixvdkdbdjxvshhzvskdvxy dgsjzvsks ysjdbdudvsk jdkdbdb
Answer:
is D
Step-by-step explanation:
for egny
I believe it's a rational number, since it's an integer.