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liq [111]
3 years ago
14

In a pool of water filled to a depth of 10 ft, calculate the fluid force on one side of a 3 ft by 4 ft rectangular plate if it r

ests vertically on its 4 ft edge at the bottom of the pool. Remember that water weighs 62.4 lb/ft3
Mathematics
1 answer:
marin [14]3 years ago
4 0

9514 1404 393

Answer:

  6,364.8 lb

Step-by-step explanation:

The centroid of the plate is its center, so is 1.5 ft above the bottom of the pool, or 8.5 ft below the surface. The area of the plate is (3 ft)(4 ft) = 12 ft². Then the fluid force is ...

  (62.4 lb/ft³)(8.5 ft)(12 ft²) = 6,364.8 lb

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Lady bird [3.3K]
220 x 440 = 96800

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I hope this helps!
8 0
3 years ago
F(x) = x2. What is g(x)?
puteri [66]

Answer:

C:  g(x) = 3x^2

Step-by-step explanation:

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5 0
3 years ago
What is the difference of polynomials (8r6s3-9r5s4+3r4s5)-(2r4s-5r6-4r5s4)
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If you would like to solve <span>(8r^6s^3 – 9r^5s^4 + 3r^4s^5) – (2r^4s^5 – 5r^3s^6 – 4r^5s^4), you can do this using the following steps:

</span>(8r^6s^3 – 9r^5s^4 + 3r^4s^5) – (2r^4s^5 – 5r^3s^6 – 4r^5s^4) = 8r^6s^3 – 9r^5s^4 + 3r^4s^5 – 2r^4s^5 + 5r^3s^6 + 4r^5s^4 = 8r^6s^3 – 5r^5s^4 + r^4s^5<span> + 5r^3s^6
</span>
The correct result would be 8r^6s^3 – 5r^5s^4 + r^4s^5<span> + 5r^3s^6.</span>
7 0
3 years ago
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nalin [4]
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4 0
3 years ago
An ANOVA procedure is used for data obtained from four populations. Four samples, each comprised of 30 observations, were taken
tatiyna

Answer:

D. 3 and 116

Step-by-step explanation:

d.f.N = k - 1 (numerator degrees of freedom) = 4 - 1 = 3

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d.f.D = N - k (denominator degrees of freedom) = 120 - 4 =116

7 0
3 years ago
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