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HACTEHA [7]
3 years ago
14

Find the midpoint of the segment with the following endpoints. (1,-10) and (8,-4)

Mathematics
1 answer:
vlada-n [284]3 years ago
3 0

Answer:

(4.5,-7)

Step-by-step explanation:

you add the x coordinates then divide them by 2

And then add the y coordinates then divide them by 2 also

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8) Vicky jogged 3 miles in hour. What was her average rate of speed in miles ) per hour? SHOW YOUR WORK A) 7 12 B) 21 c) 21 D) 1
Arisa [49]

Answer: D.

Step-by-step explanation:

the ratio of 12/4 is the same as 3

6 0
2 years ago
Can anyone help me with this math equation plsss?
Cerrena [4.2K]

Answer:

5.265

Step-by-step explanation:

3 0
3 years ago
3x - 12y = -30 and x - 6y = -12
forsale [732]

check attached file it has the answers

3x =-18

X= -12

8 0
3 years ago
Read 2 more answers
1. Use the figure below to answer the questions.<br><br> (a) Solve for x.
Dmitry [639]

Let's see what to do buddy...

_________________________________

The sum of the angles of each n-sided figure is found in the following equation :

(n - 2) \times 180

The question's figure is 5-sindes figure

so the sum the angles equal :

(5 - 2) \times 180 = 3 \times 180 = 540 \\

So we have :

90 + 107 + 144 + 138 + x = 54 0 \\

479 + x = 540

Subtract the sides of the equation minus 479

x = 540 - 479

x = 61

And we're done.

Thanks for watching buddy good luck.

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5 0
3 years ago
In a certain city of several million people, 7.7% of the adults are unemployed. If a random sample of 300 adults in this city is
Lilit [14]

Answer: 0.2643

Step-by-step explanation:

Given : The proportion of  adults are unemployed : p=0.077

The sample size = 300

By suing normal approximation to the binomial , we have

\mu=np=300\times0.077=23.1

\sigma=\sqrt{np(1-p)}=\sqrt{300\times0.077(1-0.077)}\\\\=4.61749932323\approx4.62

Now, using formula z=\dfrac{x-\mu}{\sigma}, the z-value corresponding to 26 will be :-

z=\dfrac{26-23.1}{4.62}\approx0.63

Using standard distribution table for z , we have

P-value=P(z\geq0.63)=1-P(z

=1-0.7356527=0.2643473\approx0.2643

Hence, the probability that at least 26 in the sample are unemployed  =0.2643

6 0
2 years ago
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