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2 years ago

10

Bella made apple pie. She used of a tablespoon of cinnamon and of a tablespoon of nutmeg. How much more cinnamon than nutmeg did

Bella use?

1 answer:

just olya [345]2 years ago

7 0

I believe that they used the same amount

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What is the solution to the given inequality?

xenn [34]

Answer: x ≤3

Step-by-step explanation:

Your answer is correct

7 0

1 year ago

Animals hair grows at a rate of 1 •10^-5 miles per hour.How many miles will animals Jaír grow after 500 hours?Express answer sci

babunello [35]

Answer:

0.005

Step-by-step explanation:

10^-5 =0.00001

0.00001x1= 0.00001

0.00001x 500=0.005 miles

5 0

2 years ago

A simple random sample of size nequals81 is obtained from a population with mu equals 83 and sigma equals 27. (a) Describe the

Ivanshal [37]

Answer:

a) $\bar X \sim N (\mu, \frac{\sigma}{\sqrt{n}})$

With:

$\mu_{\bar X}= 83$

$\sigma_{\bar X}=\frac{27}{\sqrt{81}}= 3$

b) $z= \frac{89-83}{\frac{27}{\sqrt{81}}}= 2$

$P(Z>2) = 1-P(Z$

c) $z= \frac{75.65-83}{\frac{27}{\sqrt{81}}}= -2.45$

$P(Z$

d) $z= \frac{89.3-83}{\frac{27}{\sqrt{81}}}= 2.1$

$z= \frac{79.4-83}{\frac{27}{\sqrt{81}}}= -1.2$

$P(-1.2$

Step-by-step explanation:

For this case we know the following propoertis for the random variable X

$\mu = 83, \sigma = 27$

We select a sample size of n = 81

Part a

Since the sample size is large enough we can use the central limit distribution and the distribution for the sampel mean on this case would be:

$\bar X \sim N (\mu, \frac{\sigma}{\sqrt{n}})$

With:

$\mu_{\bar X}= 83$

$\sigma_{\bar X}=\frac{27}{\sqrt{81}}= 3$

Part b

We want this probability:

$P(\bar X>89)$

We can use the z score formula given by:

$z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}$

And if we find the z score for 89 we got:

$z= \frac{89-83}{\frac{27}{\sqrt{81}}}= 2$

$P(Z>2) = 1-P(Z$

Part c

$P(\bar X$

We can use the z score formula given by:

$z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}$

And if we find the z score for 75.65 we got:

$z= \frac{75.65-83}{\frac{27}{\sqrt{81}}}= -2.45$

$P(Z$

Part d

We want this probability:

$P(79.4 < \bar X < 89.3)$

We find the z scores:

$z= \frac{89.3-83}{\frac{27}{\sqrt{81}}}= 2.1$

$z= \frac{79.4-83}{\frac{27}{\sqrt{81}}}= -1.2$

$P(-1.2$

8 0

2 years ago

For positive test result, the number of those who did not lie and lie are 11 and 41, respectively. Those of the negative test re

vagabundo [1.1K]

P(subject lied | negative results) = 4/19

P(negative results | subject lied) = 8/49

I am hoping that these answers have satisfied your queries and it will be able to help you in your endeavors, and if you would like, feel free to ask another question.

3 0

2 years ago

The price of a wallet $31.95 and the sales tax is 7%.

EastWind [94]

Answer:

The Answer is D - $34.19

Step-by-step explanation:

Have a nice day.

5 0

2 years ago

Read 2 more answers