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Allushta [10]
3 years ago
6

Find the coordinates of the other endpoint of the​ segment, given its midpoint and one endpoint.​ (Hint: Let​ (x,y) be the unkno

wn endpoint. Apply the midpoint​ formula, and solve the two equations for x and​ y.) midpoint ​(8​,- 1​), endpoint ​(0​,- 2​)
Mathematics
1 answer:
melomori [17]3 years ago
7 0
Mid point formula =
(x1/2+x2/2, y1/2+y2/2)

x=
x+0 = 8
/2
x+0 = 8 x 2
x = 16

y=
y+(-2) = 1
/2
y-2 =1 x2
y=2+2
y=4

(16,4)

(In this case, the midpoint (x ,y) will be represent as the answer)
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Answer:

480 units ^2

Step-by-step explanation:

I have apex trust me

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Translate into a mathematical expression: n more than 8.
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Answer:

8 + n is the answer!

Step-by-step explanation:

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Find exact values for sin θ and tan θ if cos θ = -4/9 and tan θ > 0.
julsineya [31]

Answer:

Part 1) sin(\theta)=-\frac{\sqrt{65}}{9}

Part 2) tan(\theta)=\frac{\sqrt{65}}{4}

Step-by-step explanation:

we have that

The cosine of angle theta is negative and the tangent of angle theta is positive

That means that the sine of angle theta is negative

step 1

Find sin(\theta)

we know that

sin^{2}(\theta) +cos^{2}(\theta)=1

we have

cos(\theta)=-\frac{4}{9}

substitute

sin^{2}(\theta) +(-\frac{4}{9})^{2}=1

sin^{2}(\theta) +\frac{16}{81}=1

sin^{2}(\theta)=1-\frac{16}{81}

sin^{2}(\theta)=\frac{65}{81}

square root both sides

sin(\theta)=\pm\frac{\sqrt{65}}{9}

Remember that

In this problem the sine of angle theta is negative

so

sin(\theta)=-\frac{\sqrt{65}}{9}

step 2

Find tan(\theta)

we know that

tan(\theta)=\frac{sin(\theta)}{cos(\theta)}

we have

sin(\theta)=-\frac{\sqrt{65}}{9}

cos(\theta)=-\frac{4}{9}

substitute the given values

tan(\theta)=-\frac{\sqrt{65}}{9}:-\frac{4}{9}=\frac{\sqrt{65}}{4}

3 0
3 years ago
Please help i am so confused
erma4kov [3.2K]

Answer:

{ 5,10,15,20,25,30,35}

Step-by-step explanation:

The domain of the function is the input values

Domain { 5,10,15,20,25,30,35}

7 0
3 years ago
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A courtyard has three walls with widths
wariber [46]

Using the greatest common factor, it is found that the greatest dimensions each tile can have is of 3 feet.

---------------------------

  • The widths of the walls are of <u>27 feet, 18 feet and 30 feet.</u>
  • <u>The tiles must fit the width of each wall</u>, thus, the greatest dimension they can have is the greatest common factor of 27, 18 and 30.

To find their greatest common factor, these numbers must be factored into prime factors simultaneously, that is, only being divided by numbers of which all three are divisible, thus:

27 - 18 - 30|3

9 - 6 - 10

No numbers by which all of 9, 6 and 10 are divisible, thus, gcf(27,18,30) = 3 and the greatest dimensions each tile can have is of 3 feet.

A similar problem is given at brainly.com/question/6032811

8 0
3 years ago
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