As per this theorem the two triangles are congruent if two angles and a side not between these two angles of one triangle are congruent to two corresponding angles and the corresponding side not between the angles of the other triangle.

7 0

2 years ago

Will mark brainliest, please answer correctly!!!

Mariana [72]

Answer:

The length of BC is 17 units

Step-by-step explanation:

we know that

An isosceles triangle has two equal sides and two equal angles

In this problem we have an isosceles triangle

Because

m∠ACB=m∠ABC ----> given problem

AC=AB

substitute the given values

$x+9=2x-8$

solve for x

$2x-x=9+8$

$x=17$

therefore

The length of BC is 17 units

5 0

2 years ago

Below is a series of steps Mel took to solve an equation. She got the wrong answer. Find Mel's mistake. Then, use order of opera

Inessa [10]

Answer: x = 9

Mel's mistake was in the last step, she multiplied by 2 instead of dividing by 2

Step-by-step explanation:

2x + 1 = 19

Subtract 1 from each side

2x = 18

Divide by 2

x = 9

3 0

2 years ago

Read 2 more answers

I need help with this question please.

vredina [299]

Answer:

tan(2x)=-24/7

Step-by-step explanation:

Since tan(x)=sin(x)/cos(x)

We are going to need sin(x) any time, so lets find it right away.

To do this, remember that. sin(x)^2 + cos(x)^2=1

so. $sin(x)= \sqrt{1 - (cos(x)^{2} )}=\sqrt{1-(-4/5)^{2} }$

This leads to.

$\sqrt{\frac{25-16}{25} } =\sqrt{\frac{9}{25} }=+/- 3-5$

We have obtained two solutions, -3/5 and 3/5.

We need to pick one, since not all of them are correct for our scenario, in this case, we've been told that x belongs to the range [180, 270], in this range, sin(x)<0.

So in our previous solution, we have that sin(x)= -3/5

Now, to find tang(2x), we need to apply the definition

Tang(2x)=sin(2x)/cos(2x).

Lets remember that

sin(2x)=2*sin(x)*cos(x)

cos(2x)=cos(x)^2 - sin(x)^2.

Lets evaluate our given result.

sin(2x)=2*(-3/5)*(4/5)=-24/25

cos(2x)=(-4/5)^2 - (3/5)^2=7/25

Hence

tan(2x)= -(24/25) / (7/25)=-24/7

5 0

2 years ago