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o-na [289]
3 years ago
10

Thirty-six members of the middle school choir, or 30% participated in the regional contest, as shown in the model below.

Mathematics
1 answer:
Firlakuza [10]3 years ago
3 0

Answer:

There are 120 students in the choir.

Step-by-step explanation:

Given that:

Number of members who participated in contest = 36

This represents 30% of the total members of choir at the school.

Let,

x be the number of total sutdents

30% of x = 36

\frac{30}{100}x=36

0.3x = 36

Dividing both sides by 0.3

\frac{0.3x}{0.3}=\frac{36}{0.3}\\x=120

Hence,

There are 120 students in the choir.

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Please help me on this!!​
almond37 [142]

Answer:

TW = ST

Step-by-step explanation:

RS = RW (Given)

RT = RT (reflexive property)

This makes ∆RST congruent to ∆RWT based on the reflexive property of congruence.

Therefore, the third corresponding sides, TW and ST would be congruent to each other.

Thus:

TW = ST

4 0
3 years ago
By what number must 566 be divided so as to give a quotient 15 and a remainder 11? (with steps)​
olchik [2.2K]

Answer:

37

Step-by-step explanation:

we would had to call the number needed a random value or call it x but

let's do the calculation backward to ease things up

(566 - 11) ÷15 ➡ 555 ÷ 15 = 37

6 0
3 years ago
If G is the midpoint of FH, FG= 14x + 25 and GH = 73- 2x, find FH
Alenkinab [10]
Given that G is the midpoint of FH, then:
FG=GH
hence;
14x+25=73-2x
solving for x we get:
14x+2x=73-25
16x=48
x=48/16
x=3
therefore the length FG=14x+25 will be:
14*3+25
=67
hence FH will be:
FH=67*2=134
4 0
3 years ago
16. What is the area of the shaded region in terms of Tr? [20 points]
tangare [24]
Area of the circle outside
= πr2
= π(5)2
=25 π

Area of the bigger circle inside
= π x(3)2
= 9 π
Area of the smaller circle inside
= π x (2)2
= 4 π

Area of shaded region
= 25π - 9π - 4π
= 12π square unit
6 0
2 years ago
Point A of rectangle ABCD is located at coordinates (3,7). If rectangle ABCD is translated down 7 and left 5, what are the new c
uranmaximum [27]

Answer:

The new co-ordinates are A¹ ( -2 , 0)

Step-by-step explanation:

<u><em>Step(i):</em></u>-

Point A of rectangle ABCD is located at coordinates (3,7).

<u><em>Type of transformation </em></u><em>                               </em><u><em> change of co-ordinate point</em></u>

<em>Vertical translation up 'd' units                   (x, y)→ (x, y +d)</em>

<em>Vertical translation down 'd' units              (x, y)→ (x, y -d)</em>

<em>Horizontal translation left 'C' units              (x, y)→ (x - c , y) </em>

<em>Horizontal translation right 'C' units             (x, y)→ (x + c , y) </em>

<u><em>Step(ii</em></u><em>):-</em>

<em>Given rectangle ABCD is translated down 7 and left 5</em>

<em>Given Point A(3 ,7) </em>

Vertical translation down '7' units  t

The new co-ordinate A¹ ( 3 , 7-7)→ A¹( 3, 0) and Horizontal translation left ''5' units

Now the new co-ordinates are A¹ ( 3-5 , 7-7)

<u><em>Final answer:-</em></u>

The new co-ordinates are A¹ ( -2 , 0)

7 0
3 years ago
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