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Alex17521 [72]
3 years ago
9

6 1/2 minus 5 3/4 in math

Mathematics
2 answers:
Anarel [89]3 years ago
8 0
Solve for: 6 and 1/2 minus 5 and 3/4
1. First off, we will convert both of these mixed number fractions into improper fractions.
6 and 1/2 minus 5 and 3/4
= 13/2 - 23/4
2. Next, to subtract these fractions, we need to find a common demo which is 4 so, we would leave the second fraction as is but, we need to multiply the numerator and denominator of the first fraction both by 2.
13/2 - 23/4
= 26/4 - 23/4
3. Lastly, we just need to subtract the fractions together, so, the way to do this is to just subtract the 23 from the second fraction from 26 which is in the first fraction and the denominators will remain the same which is 4, so, let’s do that.
26/4 - 23/4
= 3/4

So, in conclusion, 6 and 1/2 minus 5 and 3/4 is equal to: 3/4 or 0.75 or 75%.
Nata [24]3 years ago
7 0

Answer:

0.75, or 3/4

Step-by-step explanation:

Hope this helps! :D

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Which expression does not belong with the other three?
natka813 [3]

It's a little hard to tell from the gibberish in the choices but let's go with

Answer: 7 + 6yz

which is of second degree in its variables and has two variables.  That's two differences than the first three, which are first degree univariate.

3 0
3 years ago
Karen is starting a career as a professional wildlife photographer and plans to photograph Canadian Geese at one of the staging
balandron [24]

Answer:

$5000*0.816 = $4082

Step-by-step explanation:

It's a strange question, but based on the statement and the question it sounds like it's a poisson distribution:

* For 3 days she was able to get 2 good shots (<em>typical of that time of the year</em>)

* Good shots happen randomly

* Each day is independent of another

Let's call 'p' the probability that she makes a good shot per day

Let's call 'n' the number of days Karen is taking shots.

So, if in 3 days he got 2 good shots and that is typical at that time of the year, then the expected value for the number of good shots (X) is:

E(x)=\frac{2}{3}

For a Poisson distribution E (x)=\lambda\\\lambda= np

So:

\lambda =\frac{2}{3}

For a Poisson distribution the standard deviation is:

\sigma = \sqrt{\lambda}\\\sigma = \sqrt{\frac{2}{3}}

\sigma = 0.816 this is the standard deviation for the number of buentas taken.

So the standard deviation for income is the price of each shot per sigma

$5000*0.816 = $4082, which is the desired response.

3 0
3 years ago
Help please I need to know If it is a function of not
algol13
Look at the attachment

9. Not a function
10. Is a function
11. Not a function
12. Is a function



7 0
3 years ago
Explain your answers please
nirvana33 [79]
First is 7 second is 8 third is 3
6 0
3 years ago
In the diagram below, m A = 59°, m B = 55° and m C = 78°. Find m D.​
masya89 [10]

Answer:

D=36

Step-by-step explanation:

All angles of the triangle add up to 180. Subtract 180-59-55=66

Then the missing measurement is a vertical which means that E=66.

So then 180-78-66=36

3 0
4 years ago
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