20) 13=2f+5
2f=8
f=4
6x<=3
x<=1/2
-f-5(2f-3)=-f-10f+15=-11f+15
answer B
45+0,15*45=45+6,75=51,75$
Answer:
No
Step-by-step explanation:
7997
Got me there but i think its 325500
Answer:
0.0143
Step-by-step explanation:
In this question, we are asked to use the binomial distribution to calculate the probability that 10 or fewer passengers from a sample of MIT data project sample were on American airline flights.
We proceed as follows;
The probability that a passenger was an American flight is 15.5%= 15.55/100 = 0.155
Let’s call this probability p
The probability that he/she isn’t on the flight, let’s call this q
q =1 - p= 0.845
Sample size, n = 155
P(X < A) = P(Z < (A - mean)/standard deviation)
Mean = np
= 125 x 0.155
= 19.375
Standard deviation = √npq
= √ (125 x 0.155x 0.845)
= 4.0462
P(10 or fewer passengers were on American Airline flights) = P(X \leq 10)
= P(Z < (10.5 - 19.375)/4.0462)
= P(Z < -2.19)
= 0.0143
Answer:
Step-by-step explanation:
the answer is unknown because there is no answer to that question and if there was it would be odd an would not make sence so that is a true of false question
