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3 years ago

8

Solve the quadratic equation by factoring. 7K^2-6k+3=3

2 answers:

ivann1987 [24]3 years ago

6 0

Subtract 3 to get:

7k^2-6k=0

Clearly, we can factor out a k to find that:

k(7k-6)=0

If either k or 7k-6 is zero, the whole expression is zero, so our solutions are zero and 6/7.

Ilya [14]3 years ago

6 0

We make one side zero
subtract 3 from both sides
7k^2-6k=0
factor out k
(k)(7k-6)=0
set each to zero
k=0

7k-6=0
add 6 to both sides
7k=6
diivde by 7
k=6/7

k=0 or 6/7

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Read 2 more answers

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hoa [83]

The partial fraction decomposition is $\frac{8x + 19}{(x + 8)(x - 1)} = \frac{5}{x + 8} + \frac{3}{x - 1}$

<h3>How to determine the decomposition?</h3>

The fraction is given as:

$\frac{8x + 19}{(x + 8)(x - 1)}$

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$\frac{8x + 19}{(x + 8)(x - 1)} = \frac{A}{x + 8} + \frac{B}{x - 1}$

Take the LCM

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brainly.com/question/12783868

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