Question

Solve the quadratic equation by factoring. 7K^2-6k+3=3

Answer 1

Subtract 3 to get:

7k^2-6k=0

Clearly, we can factor out a k to find that:

k(7k-6)=0

If either k or 7k-6 is zero, the whole expression is zero, so our solutions are zero and 6/7.

Answer 2

We make one side zero
subtract 3 from both sides
7k^2-6k=0
factor out k
(k)(7k-6)=0
set each to zero
k=0

7k-6=0
add 6 to both sides
7k=6
diivde by 7
k=6/7

k=0 or 6/7