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bagirrra123 [75]
3 years ago
7

What equation (Ex: Y=mx+b) would have an intersection with x=y on the origin (0,0)? PLEASE HELP!!

Mathematics
1 answer:
vivado [14]3 years ago
5 0
(2, -1) I think, I could be wrong.
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Evaluate the definite integral. <br> 1 x4(1 + 2x5)5 dx.
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Answer:

Step-by-step explanation:

Given the definite integral \int\limits {\dfrac{x^4}{(1-2x^5)^5} } \, dx, we to evaluate it. Using integration by substitution method.

Let u = 1-2x⁵ ...1

du/dx = -10x⁴

dx = du/-10x⁴.... 2

Substitute equation 1 and 2 into the integral function and evaluate the resulting integral as shown;

= \int\limits {\dfrac{x^4}{u^5} } \, \dfrac{du}{-10x^4}

= \dfrac{-1}{10} \int\limits {\dfrac{du}{u^5} }  \\\\= \dfrac{-1}{10} \int\limits {{u^{-5}du }  \\= \dfrac{-1}{10} [{\frac{u^{-5+1}}{-5+1}]  \\\\= \dfrac{-1}{10} ({\frac{u^{-4}}{-4})\\\\

= \dfrac{u^{-4}}{40} \\\\\\= \dfrac{1}{40u^4} +C

substitute u = 1-2x⁵ into the result

= \dfrac{1}{40(1-2x^5)^4} +C

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The <span>given the piecewise function is :
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f(x) = \[ \begin{cases} &#10;      2x & x \ \textless \  1 \\&#10;      5 & x=1 \\&#10;      x^2 & x\ \textgreater \ 1 &#10;   \end{cases}&#10;\]

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To find f(-2) ⇒ substitute with x = 5 in the function → 2x
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∴ f(1) = 5
================================
So, the statements which are true:<span>
\framebox {B. f(2) = 4} \ \framebox {D. f(1) = 5}</span><span></span>
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Answer:

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Step-by-step explanation:


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Answer:

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