Answer:
The nonzero value of c will be:
Step-by-step explanation:
Given the function
![f\left(x\right)=\:x^2-4x-c](https://tex.z-dn.net/?f=f%5Cleft%28x%5Cright%29%3D%5C%3Ax%5E2-4x-c)
![f\left(c\right)=\:c^2-4c-c](https://tex.z-dn.net/?f=f%5Cleft%28c%5Cright%29%3D%5C%3Ac%5E2-4c-c)
as
![f(c) = c](https://tex.z-dn.net/?f=f%28c%29%20%3D%20c)
so
![c=\:c^2-4c-c](https://tex.z-dn.net/?f=c%3D%5C%3Ac%5E2-4c-c)
switching the sides
![c^2-4c-c=c](https://tex.z-dn.net/?f=c%5E2-4c-c%3Dc)
subtract c from both sides
![c^2-4c-c-c=c-c](https://tex.z-dn.net/?f=c%5E2-4c-c-c%3Dc-c)
![c^2-6c=0](https://tex.z-dn.net/?f=c%5E2-6c%3D0)
![c\left(c-6\right)=0](https://tex.z-dn.net/?f=c%5Cleft%28c-6%5Cright%29%3D0)
Using the zero factor principle
![\:If}\:ab=0\:\mathrm{then}\:a=0\:\mathrm{or}\:b=0\:\left(\mathrm{or\:both}\:a=0\:\mathrm{and}\:b=0\right)](https://tex.z-dn.net/?f=%5C%3AIf%7D%5C%3Aab%3D0%5C%3A%5Cmathrm%7Bthen%7D%5C%3Aa%3D0%5C%3A%5Cmathrm%7Bor%7D%5C%3Ab%3D0%5C%3A%5Cleft%28%5Cmathrm%7Bor%5C%3Aboth%7D%5C%3Aa%3D0%5C%3A%5Cmathrm%7Band%7D%5C%3Ab%3D0%5Cright%29)
![c=0\quad \mathrm{or}\quad \:c-6=0](https://tex.z-dn.net/?f=c%3D0%5Cquad%20%5Cmathrm%7Bor%7D%5Cquad%20%5C%3Ac-6%3D0)
so, the solutions to the quadratic equations are:
![c=0,\:c=6](https://tex.z-dn.net/?f=c%3D0%2C%5C%3Ac%3D6)
Therefore, a nonzero value of c will be:
The cost of the monthly fee is 50$.. if the joining fee is 100.. take 200 and subtract that fee since it is included in the total. You’re left with 100. Note, the 200 is calculated for a 2 month period, so split the remaining 100 ,from the total 200, into 2. You’re left with 50 each month.
T=(C-100)/2 (T being 1 month) (C being the total cost/200)
Hopefully
1 to 4
150mm is the same as 15cm
15cm:60cm
both divisible by 15
1cm:4cm
1 to 4
The ones with a square in a picture is a 90 degree angle the rest are a 180