Question

The puppy needs to catch a train that is moving at 8 km/h. She is 100m away and running at 10 km/h. How far will the train have traveled before the puppy is able to jump on?​

Answer 1

Answer: 400 m

Step-by-step explanation:

Given

Speed of train is $v_t=8\ km/h$

Speed of Puppy $v_p=10\ km/h$

Puppy is 100 m away from the train

Suppose train has moved x km before the puppy catches the train

Therefore puppy has to travel 100 m and  x km to catch the train

$\Rightarrow t_p=t_t\\\text{Insert the values}\\\\\Rightarrow \dfrac{0.1+x}{10}=\dfrac{x}{8}\\\\\Rightarrow 8(0.1+x)=10x\\\Rightarrow 0.8+8x=10x\\\Rightarrow 0.8=2x\\\Rightarrow x=0.4\ km\ or\ 400\ m$

Thus, train has traveled 400 m.

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