solve the following inequality. Then click on the graph until the correct one is displayed. y ≥ |x - 1|
1 answer:
You might be interested in
Answer:
Check below, please.
Step-by-step explanation:
Hi, there!
Since we can describe eccentricity as
a) Eccentricity close to 0
An ellipsis with eccentricity whose value is 0, is in fact, a degenerate one almost a circle. An ellipse whose value is close to zero is almost a degenerate circle. The closer the eccentricity comes to zero, the more rounded gets the ellipse just like a circle. (Check picture, please)
b) Eccentricity =5
An eccentricity equal to 5 implies that the distance between the Foci has to be five (5) times larger than the half of its longer axis! In this case, there can't be an ellipse since the eccentricity must be between 0 and 1 in other words:
c) Eccentricity close to 1
In this case, the eccentricity close or equal to 1 We must conceive an ellipse whose measure for the half of the longer axis a and the distance between the Foci 'c' they both have the same size.
we conclude that the center of the circle is the point (-5, 0).
<h3>How to find the center of the circle equation?</h3>The equation of a circle with a center (a, b) and a radius R is given by:
Here we are given the equation:
Completing squares, we get:
Now we can add and subtract 25 to get:
Comparing that with the general circle equation, we conclude that the center of the circle is the point (-5, 0).
If you want to learn more about circles:
#SPJ1