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2 years ago

Brain bought 2 shirts for 14.50 each and a pair of shoes for 29.99 the sales tax was 6%

2 answers:

8 0

2* $14.50+ $29.99= $58.99

$58.99* (6/100)= $3.54
The sales tax is $3.54~

$58.99+ $3.54= $62.53
Brian had to pay a total of $62.53~

Sedbober [7]2 years ago

6 0

Cost of each shirt bought by Brain = 14.50
Then
Cost of 2 shirts bought by Brain = 2 * 14.50
      = 29
Cost of a pair of shoes = 29.99
Total amount spent by Brain before tax = 29 + 29.99
   = 58.99
Percentage of sales tax that needs to be paid = 6%
Amount of sales tax that needs to be [paid = (6/100) * 58.99
   = 353.94/100
   = 3.54
So
the total amount spent by Brain including tax = 58.99 + 3.54
   = 62.53
I hope this is the answer you were looking for.

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If the flour to sugar ratio is 4 cups flour to 1 cup sugar, then how much sugar do you need if you only use 2 cups of flour?

miss Akunina [59]

you would need half a cup of sugar

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2 years ago

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Si una galleta de chocolate aporta un aproximado de 150 kcal y un viaje en bicicleta se quema por media hora se que mas 340 kcal

Elanso [62]

Answer:

Una persona necesitará 2 horas y 30 minutos de viaje en bicicleta para quemar el contenido kilocalórico de cinco galletas.

Step-by-step explanation:

De acuerdo con este problema, la cantidad de calorías que se quema es directamente proporcional al tiempo de viaje en bicicleta. Si sabemos que una galleta aporta 150 kilocalorías, entonces 5 galletas equivalen a 750 kilocalorías.

Por regla de tres simple calculamos el tiempo requerido para quemar 750 kilocalorías:

$x = 30\,min \times \frac{750\,kcal}{150\,kcal}$

$x = 150\,min$

Es decir, una persona necesitará 2 horas y 30 minutos de viaje en bicicleta para quemar el contenido kilocalórico de cinco galletas.

6 0

2 years ago

During the first six months of operation, Abdoul's lemonade stand made a profit of $50 per month. In the next three months it ha

MrMuchimi

profit, p = 6 × $50 = $300

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3 years ago

PLEASE HELP!! Ill mark the brainliest!!!!

ira [324]

Answer:

x = 5√2

y = 5√6

z = 5√3

ΔABC ~ ΔBDC ~ ΔADB

Step-by-step explanation:

ΔABC, ΔBDC, and ΔADB are all similar triangles to each other.

By definition of similar triangles, the corresponding sides have the same ratios.

CD from ΔBDC corresponds to BD from ΔADB, and BD from ΔBDC corresponds to AD from ΔADB. So:

CD / BD = BD / AD

10 / x = x / 5

x² = 50

x = 5√2

Since ΔBDC is right, we can use the Pythagorean Theorem to solve for y:

CD² + BD² = BC²

10² + (5√2)² = y²

y² = 100 + 50 = 150

y = 5√6

Again, since ΔΔABD is right, we can use the Pythagorean Theorem to solve for z:

AD² + BD² = AB²

5² + (5√2)² = z²

z² = 25 + 50 = 75

z = 5√3

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3 years ago

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Solve these linear equations in the form y=yn+yp with yn=y(0)e^at.

WINSTONCH [101]

Answer:

a) $y(t) = y_{0}e^{4t} + 2$ . It does not have a steady state

b) $y(t) = y_{0}e^{-4t} + 2$ . It has a steady state.

Step-by-step explanation:

a) $y' -4y = -8$

The first step is finding $y_{n}(t)$ . So:

$y' - 4y = 0$

We have to find the eigenvalues of this differential equation, which are the roots of this equation:

$r - 4 = 0$

$r = 4$

So:

$y_{n}(t) = y_{0}e^{4t}$

Since this differential equation has a positive eigenvalue, it does not have a steady state.

Now as for the particular solution.

Since the differential equation is equaled to a constant, the particular solution is going to have the following format:

$y_{p}(t) = C$

$(y_{p})' -4(y_{p}) = -8$

$(C)' - 4C = -8$

C is a constant, so (C)' = 0.

$-4C = -8$

$4C = 8$

$C = 2$

The solution in the form is

$y(t) = y_{n}(t) + y_{p}(t)$

$y(t) = y_{0}e^{4t} + 2$

b) $y' +4y = 8$

The first step is finding $y_{n}(t)$ . So:

$y' + 4y = 0$

We have to find the eigenvalues of this differential equation, which are the roots of this equation:

$r + 4 =$

$r = -4$

So:

$y_{n}(t) = y_{0}e^{-4t}$

Since this differential equation does not have a positive eigenvalue, it has a steady state.

Now as for the particular solution.

Since the differential equation is equaled to a constant, the particular solution is going to have the following format:

$y_{p}(t) = C$

$(y_{p})' +4(y_{p}) = 8$

$(C)' + 4C = 8$

C is a constant, so (C)' = 0.

$4C = 8$

$C = 2$

The solution in the form is

$y(t) = y_{n}(t) + y_{p}(t)$

$y(t) = y_{0}e^{-4t} + 2$

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3 years ago