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horsena [70]
3 years ago
5

Eva marked 18% of the e-mails in her Inbox as Important. If she has 150 e-mails in her Inbox, how many did she mark as Important

?
A n=0.18(150)
B 150n= 0.18
C 0.18n=150
D n=0.18/150
Mathematics
2 answers:
sdas [7]3 years ago
8 0

Answer:

A

Step-by-step explanation:

To find the percent of a number, write the percent as a decimal and multiply it by the number

Arisa [49]3 years ago
8 0

Answer:

A n=0.18(150)

Step-by-step explanation:

let's take number of important emails as " n "

according to the question

=》n =

\frac{18}{100}  \times 150

( since % = division by 100 )

=》n =

0.18 \times 150

=》 hence, n = 0.18(150)

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Write an equation of the parabola in vertex form.
Katena32 [7]

Answer:

f (x) = a(x - h)2 + k, where (h, k) is the vertex of the parabola. ... When written in "vertex form": • (h, k) is the vertex of the parabola, and x = h is the axis of symmetry.

6 0
4 years ago
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Solve ΔABC with ABC=51°, c=8 and a=11. Draw a diagram.
Rashid [163]

To solve a triangle means to obtain al the missing parts of the triangle.

<h3>How do you solve a triangle?</h3>

To solve a triangle means to obtain al the missing parts of the triangle. Now we have the following information;

<ABC = 51°

c = 8

a = 11

Then;

b^2 = a^2 + c^2 - 2acCos B

b^2 = (11)^2 + (8)^2 - [2 * 11 * 8 * cos 51]

b^2 = 121 + 64 - 55.38

b = 11.39

Now;

a/sinA = b/sinB

asinB = bsinA

sinA = asinB/b

sinA = 11 * sin 51/11.39

A = 48.6 or 49°

C = 180 - (49 + 51)

C = 80°

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7 0
2 years ago
I need help...like fast plezz
liubo4ka [24]

Answer:

80°

Step-by-step explanation:

176 - 32 = 144

144(4/9) = 80°

the answer is 80°

6 0
3 years ago
(Ross 5.15) If X is a normal random variable with parameters µ " 10 and σ 2 " 36, compute (a) PpX ą 5q (b) Pp4 ă X ă 16q (c) PpX
pochemuha

Answer:

(a) 0.7967

(b) 0.6826

(c) 0.3707

(d) 0.9525

(e) 0.1587

Step-by-step explanation:

The random variable <em>X</em> follows a Normal distribution with mean <em>μ</em> = 10 and  variance <em>σ</em>² = 36.

(a)

Compute the value of P (X > 5) as follows:

P(X>5)=P(\frac{x-\mu}{\sigma}>\frac{5-10}{\sqrt{36}})\\=P(Z>-0.833)\\=P(Z

Thus, the value of P (X > 5) is 0.7967.

(b)

Compute the value of P (4 < X < 16) as follows:

P(4

Thus, the value of P (4 < X < 16) is 0.6826.

(c)

Compute the value of P (X < 8) as follows:

P(X

Thus, the value of P (X < 8) is 0.3707.

(d)

Compute the value of P (X < 20) as follows:

P(X

Thus, the value of P (X < 20) is 0.9525.

(e)

Compute the value of P (X > 16) as follows:

P(X>16)=P(\frac{x-\mu}{\sigma}>\frac{16-10}{\sqrt{36}})\\=P(Z>1)\\=1-P(Z

Thus, the value of P (X > 16) is 0.1587.

**Use a <em>z</em>-table for the probabilities.

8 0
3 years ago
I REALLY NEED THIS NOW. PLEASE HELP ME!!
Andre45 [30]

Answer:

4*-2... answer D. is correct :)

7 0
4 years ago
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