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SVETLANKA909090 [29]
4 years ago
7

1011001 in decimal please hurry up​

Computers and Technology
1 answer:
gtnhenbr [62]4 years ago
8 0

Answer:

So, 89 is the decimal equivalent of the binary number 1011001.

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We piped the results of the Get-Process cmdlet to the Sort-Object cmdlet to sort them in descending order. Which property was us
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This program builds on the program developed in part
soldi70 [24.7K]

Answer:

The solution is in C++

Explanation:

// C++ programs to search a word in a 2D grid  

#include<bits/stdc++.h>  

using namespace std;  

// Rows and columns in given grid  

#define R 3  

#define C 14  

// For searching in all 8 direction  

int x[] = { -1, -1, -1, 0, 0, 1, 1, 1 };  

int y[] = { -1, 0, 1, -1, 1, -1, 0, 1 };  

// This function searches in all 8-direction from point  

// (row, col) in grid[][]  

bool search2D(char grid[R][C], int row, int col, string word)  

{  

// If first character of word doesn't match with  

// given starting point in grid.  

if (grid[row][col] != word[0])  

return false;  

int len = word.length();  

// Search word in all 8 directions starting from (row,col)  

for (int dir = 0; dir < 8; dir++)  

{  

 // Initialize starting point for current direction  

 int k, rd = row + x[dir], cd = col + y[dir];  

 // First character is already checked, match remaining  

 // characters  

 for (k = 1; k < len; k++)  

 {  

  // If out of bound break  

  if (rd >= R || rd < 0 || cd >= C || cd < 0)  

   break;  

  // If not matched, break  

  if (grid[rd][cd] != word[k])  

   break;  

  // Moving in particular direction  

  rd += x[dir], cd += y[dir];  

 }  

 // If all character matched, then value of must  

 // be equal to length of word  

 if (k == len)  

  return true;  

}  

return false;  

}  

// Searches given word in a given matrix in all 8 directions  

void patternSearch(char grid[R][C], string word)  

{  

// Consider every point as starting point and search  

// given word  

for (int row = 0; row < R; row++)  

for (int col = 0; col < C; col++)  

 if (search2D(grid, row, col, word))  

  cout << "pattern found at " << row << ", "

   << col << endl;  

}  

// Driver program  

int main()  

{  

char grid[R][C] = {"GEEKSFORGEEKS",  

    "GEEKSQUIZGEEK",  

    "IDEQAPRACTICE"

    };  

patternSearch(grid, "GEEKS");  

cout << endl;  

patternSearch(grid, "EEE");  

return 0;  

}  

8 0
3 years ago
A 32-bit computer has two selector channels and one multiplexor channel. Each selector channel supports two hard disks and two D
Anit [1.1K]

Answer:

Maximum Aggregate I/O Transfer Rate = 1630kb/s

Explanation:

Given

Transfer rate of

Disk Drive = 800Kb/s

DVD Drive = 700Kb/s

Printer = 10Kb/s

VDT = 2Kb/s

Units

DVD = 2

Hard Disk = 2

Printers = 2

VDT Channels = 5

Only one device at a time can be serviced on a selector channel

Both cannot be active at a time

So, the device with higher transfer rate will be granted access (Disk Drive, 800Kb/s)

Maximum aggregate I/O transfer rate in this system is calculated by:

Summation of transfer rate of each device

= 800 * 2 + 2 * 10 + 5 * 2

= 1600 + 20 + 10

= 1630kb/s

7 0
3 years ago
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