Answer:
No it doesnt because 6 does not equal 2
Base case: if <em>n</em> = 1, then
1² - 1 = 0
which is even.
Induction hypothesis: assume the statement is true for <em>n</em> = <em>k</em>, namely that <em>k</em> ² - <em>k</em> is even. This means that <em>k</em> ² - <em>k</em> = 2<em>m</em> for some integer <em>m</em>.
Induction step: show that the assumption implies (<em>k</em> + 1)² - (<em>k</em> + 1) is also even. We have
(<em>k</em> + 1)² - (<em>k</em> + 1) = <em>k</em> ² + 2<em>k</em> + 1 - <em>k</em> - 1
… = (<em>k</em> ² - <em>k</em>) + 2<em>k</em>
… = 2<em>m</em> + 2<em>k</em>
… = 2 (<em>m</em> + <em>k</em>)
which is clearly even. QED
Answer:
Step-by-step explanation:
u have an arithmetic sequence...ur adding 3 to every number to get to the next number
3 + 3 = 6
6 + 3 = 9
9 + 3 = 12
12 + 3 = 15
and so on...
Step-by-step explanation:
15=2c+7
15-7=2c
8=2c
8/2=c
4=c
c=4
