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3 years ago

Solve: (x + 5)^2 + 15 = 64

1 answer:

3 0

$(x + 5)^{2}$ + 15 = 64 Subtract 15 from both sides
<span> $(x + 5)^{2}$ = 49 Find the square root of both sides to cancel out the </span> $(x + 5) ^{2}$
x + 5 = 7 Subtract 5 from both sides
x = 2
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</span>

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The tile pattern below is made up of trapezoids and rhombuses. What is the area of each figure in the pattern?

shutvik [7]

The area of the rhombus and trapezoid from the figure are 2 square in and 5 square in respectively

<h3>How to find the area of a trapezoid and rhombus?</h3>

The given pattern consists of rhombus and trapezoids

The formula for calculating the area of rhombus is expressed as:

A = pq/2

Area of trapezoid = 0.5(a+b)h

Given the following

height = 2in

a = 2in

b = 3in

Ara of rhombus = 1(4)/2 = 2 square inches

Area of the trapezoid = 0.5(2+3) * 2

Area of the trapezoid = 5 square inches

Hence the area of the rhombus and trapezoid from the figure are 2 square in and 5 square in respectively

Learn more on area of rhombus and trapezoid here: brainly.com/question/2456096

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2 years ago

Somebody help me with this

zubka84 [21]

Answer:

Step-by-step explanation:

when multiplying fractions it doesn’t matter if they have the same denominator (bottom) just multiply straight across

(6/12)x(6/3)

36/36

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3 years ago

WILL GIVE BRAINLIEST!! (Look at photo if confused)

andrey2020 [161]

Answer:

1. B. 9

2. A. 4

3. D. 9 × 9 × 9 × 9

4. C. 6,561

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3 years ago

Read 2 more answers

Roberta has $10,540 to invest. She plans to invest her money in certificates of deposit (CDs) that have 2.1% interest, a stock p

ira [324]

Answer:

The amount invested in CDs is $1,340

The amount invested in the stock portafolio is $6,900

The amount invested in the saving accounts is $2,300

Step-by-step explanation:

Let

x ---->the amount invested in CDs at 2.1%

y ---> the amount invested in the stock portfolio at 2.5%

z ---> the amount invested in the savings account at 1.5%

$x+y+z=10,540$ ----> equation A

$z=\frac{1}{3}y$ ----> equation B

substitute equation B in equation A

$x+y+\frac{1}{3}y=10,540$

$x+\frac{4}{3}y=10,540$

$x=10,540-\frac{4}{3}y$ ----> equation C

we know that

The total interest earned by the three amount must be equal to $231.69

$0.021x+0.025y+0.015z=231.69$ ----> equation D

substitute equation B and equation C in equation D

$0.021(10,540-\frac{4}{3}y)+0.025y+0.015(\frac{1}{3}y)=231.69$

solve for y

$221.34-0.0315y+0.025y+0.005y=231.69$

$0.0015y=231.69-221.34$

$0.0015y=10.35$

$y=\$6,900$

<em>Find the value of x</em>

$x=10,540-\frac{4}{3}(6,900)$

$x=\$1,340$

<em>Find the value of z</em>

$z=\frac{1}{3}(6,900)$

$z=\$2,300$

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3 years ago

Find the length and breadth of the rectangle if the area is x^2+3x+4ax+12a

BlackZzzverrR [31]

Answer:

Area =(x+3)(x+4a)

so sides = 3 and 4a

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3 years ago