Given the function f (x) = 3x, find the value of f-1 (81).
For this case, the first thing you should do is rewrite the function.
We have then:
y = 3 ^ x
From here, we clear the value of x:
log3 (y) = log3 (3 ^ x)
log3 (y) = x
Then, we rewrite the function again:
f (x) ^ - 1 = log3 (x)
Now, we evaluate the inverse function for x = 81:
f (81) ^ - 1 = log3 (81)
f (x) ^ - 1 = 4
Answer:
the value of f-1 (81) is:
f (x) ^ - 1 = 4
Answer: (4,-5)
Step-by-step explanation:
8y = -40
(divide by 8)
y = -5
(plug it in to one of the equations)
3x + 6*-5 = -18
3x + -30 = -18
3x = 12
x = 4
Answer:
Hi there!
Your answers are:
1) 38^10
2) 20^3
Step-by-step explanation:
1) Theres a property that goes like this:
(x^m)^n = x^mn
When you do a power of a power, you multiply them together!
2) There's a property that looks like this:
x^ m / x^n = x^ m-n
When dividing exponents, subtract!
Hope this helps!
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