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Soloha48 [4]
3 years ago
5

A salesman has a car for sale for $5000. He decides to increase the price by 40%. When no one buys the car, he decreases the new

price by 10%.
What is the final price of the car?
Mathematics
2 answers:
Amiraneli [1.4K]3 years ago
5 0

Answer:

0 because it fell apart after he glued it togheter

Step-by-step explanation:

Crazy boy [7]3 years ago
5 0

Answer:

$6300

Step-by-step explanation:

original price: $5000

increase price by 40%: $5000×1.4=$7000

decrease new price by 10%: %7000×0.9=$6300

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What is the simplified form of each expression?<br><br> (7 – c)(–1)
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-7+c

Step-by-step explanation:

distribute the - 1

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3 years ago
A couple needs $55,000 as a down payment for a home. If they invest the $40,000 they have at 4% compounded quarterly, how long w
slava [35]

Answer:

8 years

Step-by-step explanation:

Compound interest formula

A(t)= A_0(1+\frac{r}{n})^{nt}

A(t) is the final amount 55000

A_0= 40000, r= 4% = 0.04, for quarterly n=4

55000=40000(1+\frac{0.04}{4})^{4t}

divide both sides by 40000

1375=(1+\frac{0.04}{4})^{4t}

1375=(1.01)^{4t}

Take ln on both sides

ln(1375)=4tln(1.01)

divide both sides by ln(1.01)

\frac{ln 1375}{ln 1.01}=4t

Divide both sides by 4

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So it takes 8 years

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3 years ago
Find the percent increase from 200 to 500​
Mnenie [13.5K]

Answer:

The answer is a 150% increase!

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
1.) Divide $80 among three people so that the second will have twice as much as the first, and the third will have $5 less than
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1 ) The first person will have $17. The second person will have $34 and the third person will $29.
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3 years ago
The following observations are on stopping distance (ft) of a particular truck at 20 mph under specified experi- mental conditio
zzz [600]

Answer:

see explaination

Step-by-step explanation:

Data : 32.1 , 30.6 , 31.4 , 30.4 , 31.0 , 31.9

Mean X-bar = 31.23

SD = 0.689

a)

Null Hypothesis : Xbar = mu

Alternate Hypothesis : Xbar > mu

z = (Xbar - mu) / (SD/sqrt(n))

= (31.23 - 30 ) /(0.689/sqrt(6))

= 4.372

P-value = ~0

Since P-vale < 0.01 , we will reject null hypothesis.

The data suggest that true average stopping ditance exceeds the maximum.

b)

i) SD = 0.65

mu = 31

z = (Xbar - mu) / (SD/sqrt(n))

= (31.23 - 31) /(0.65/sqrt(6))

= 0.867

P-value = 0.3859 Answer

ii) SD = 0.65

mu = 32

z = (Xbar - mu) / (SD/sqrt(n))

= (31.23 - 32) /(0.65/sqrt(6))

= -2.9

P-value = 0.0037 Answer

c)

i) SD = 0.8

mu = 31

z = (Xbar - mu) / (SD/sqrt(n))

= (31.23 - 31) /(0.8/sqrt(6))

= 0.704

P-value = 0.4814 Answer

ii) SD = 0.8

mu = 32

z = (Xbar - mu) / (SD/sqrt(n))

= (31.23 - 32) /(0.8/sqrt(6))

= -2.357

P-value = 0.0184 Answer

The probabilities obtained in part c are comparatively higher than that of part b.

d)

i) For alpha =0.01

z = (Xbar - mu) / (SD/sqrt(n))

=> -2.32 = (31.23 - 31) /(0.65/sqrt(n))

=> (0.65/sqrt(n)) = (31.23 - 31)/-2.32

=> sqrt(n) = (0.65*(-2.32)) / (31.23 - 31)

=> n = 43 Answer

ii) For beta =0.10

z = (Xbar - mu) / (SD/sqrt(n))

=> -1.28 = (31.23 - 31) /(0.65/sqrt(n))

=> (0.65/sqrt(n)) = (31.23 - 31)/-1.28

=> sqrt(n) = (0.65*(-1.28)) / (31.23 - 31)

=> n = 13 Answer

4 0
2 years ago
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