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Ratling [72]
3 years ago
14

4x + 3y = 1 x - 3y = -11

Mathematics
2 answers:
Ray Of Light [21]3 years ago
6 0

Answer:

x=-2, y=3

Step-by-step explanation:

4x + 3y = 1.......... Equ 1

x - 3y = -11...........Equ 2

5x=-10

x=-2

From equ 1

4x + 3y =1

4(-2)+3y=1

-8+3y=1

3y=1+8

3y=9

y=3

JulijaS [17]3 years ago
4 0

Answer:

(- 2, 3 )

Step-by-step explanation:

Given the 2 equations

4x + 3y = 1 → (1)

x - 3y = - 11 → (2)

Adding the 2 equations term by term will eliminate the y- term

5x + 0 = - 10

5x = - 10 ( divide both sides by 5 )

x = - 2

Substitute x = - 2 into either of the 2 equations and solve for y

Substituting into (1)

4(- 2) + 3y = 1

- 8 + 3y = 1 ( add 8 to both sides )

3y = 9 ( divide both sides by 3 )

y = 3

solution is (2, - 3 )

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a rectangular prism measures 3 in by 8 in by 9 in. what is the side length of a cube with the same volume?
Novay_Z [31]

Answer:

6 in.

Step-by-step explanation:

Rectangular prism

V = lwh       l = 8   W = 3    h = 9

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V = s^{3}   where s = length of side

216 = s^{3}

s = \sqrt[3]{216}  = 6

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Read 2 more answers
The following parts refer to the letters: LAMEFIREALARM. Recall that "word" means distinguishable letter arrangements. (a) How m
larisa86 [58]

Answer:

Step-by-step explanation:

The word "LAMEFIREALARM" word consists of

2L , 2M, 2E , 2R , 3A , F and I

no of words with the above letters such that M's are not together

=Total No of words- M's are together

Total no of words=\frac{13!}{4\times 2!\times 3!}=64,864,800

When M's are together . considering 2 M's as one

therefore there are \frac{12!}{3\times 2!\times 3!}=9,979,200

No of ways=\frac{13!}{4\times 2!\times 3!}-\frac{12!}{3\times 2!\times 3!}=54,885,600

(b)No of ways such that M's are separated by at least 2 letters

at least  2 letter means 2 letter, 3 letter ......11 letters

So we have to subtract no of ways where there are 1 letter in between M's from total no of ways where 2 M's are not next to each other

No of ways in which there is 1 letter between 2 M's

This can be done by considering 11 cases

In first case Place first M in Starting Position and 2 M on third place

Second case place First M in 2 nd Position and second M on 4 th place

Similarly For 11th case

Place first M in 11th place and second M on 13th place

Total ways

=\frac{11\times 11!}{3!\times 2!\times 2!\times 2!}

So , the total number of arrangements of the letters of the word LAMEFIREALARM where the two M's are separated by atleast two letters is

=\frac{13!}{4\times 2!\times 3!}-\frac{12!}{3\times 2!\times 3!}-\frac{11\times 11!}{3!\times 2!\times 2!\times 2!}

=45738000

7 0
3 years ago
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