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jekas [21]
3 years ago
15

Andrea had 32 problems to do for mathematics homework over the weekend. She did 1/4 of the problems on Friday night, and on Satu

rday she did 1/4 of the problems that were left to do. What was the total number of problems that Andrea needed to do on Saturday in order to complete her mathematics homework?
Mathematics
2 answers:
S_A_V [24]3 years ago
8 0

Answer:

18

Step-by-step explanation:

1/4 of 32 is 8 so 8 - 32 = 24

1/4 of 24 is 6 so 3 - 24 = 18

Vlad [161]3 years ago
6 0
32/4 =8
24/4= 6
18 is left
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Find the appropriate rejection regions for the large-sample test statistic z in these cases. (Round your answers to two decimal
Usimov [2.4K]

Answer:

a) We have that the significance is given by \alpha =0.01 and we know that we have a right tailed test.

So for this case we need to look in the normal standard dsitribution a critical value that accumulates 1% of the area on the right and 99% of the area on the left. This value can be founded with the following excel code:

"=NORM.INV(1-0.01,0,1)"

And we got for this case z_{crit}=2.33

So then the rejection region would be z>2.33

b) We have that the significance is given by \alpha =0.05, \alpha/2 =0.025 and we know that we have a two tailed test.

So for this case we need to look in the normal standard dsitribution a critical value that accumulates 2.5% of the area on the right and 97.5% of the area on the left. This value can be founded with the following excel code:

"=NORM.INV(1-0.025,0,1)"

And we got for this case z_{crit}=\pm 1.96

So then the rejection region would be z>1.96 \cup z

Step-by-step explanation:

Part a

We have that the significance is given by \alpha =0.01 and we know that we have a right tailed test.

So for this case we need to look in the normal standard dsitribution a critical value that accumulates 1% of the area on the right and 99% of the area on the left. This value can be founded with the following excel code:

"=NORM.INV(1-0.01,0,1)"

And we got for this case z_{crit}=2.33

So then the rejection region would be z>2.33

Part b

We have that the significance is given by \alpha =0.05, \alpha/2 =0.025 and we know that we have a two tailed test.

So for this case we need to look in the normal standard dsitribution a critical value that accumulates 2.5% of the area on the right and 97.5% of the area on the left. This value can be founded with the following excel code:

"=NORM.INV(1-0.025,0,1)"

And we got for this case z_{crit}=\pm 1.96

So then the rejection region would be z>1.96 \cup z

7 0
3 years ago
2x+3y=-12<br> 2x+t=-16<br> X=. Y=<br> Help plz
8090 [49]

<u>To make this problem solvable, I have replaced the 't' in the second equation for a 'y'.</u>

Answer:

<em>x = -9</em>

<em>y = 2</em>

Step-by-step explanation:

<u>Solve the system:</u>

2x + 3y = -12       [1]

2x + y = -16       [2]

Subtracting [1] and [2]:

3y - y = -12 + 16

2y = 4

y = 4/2 = 2

From [1]:

2x + 3(2) = -12

2x + 6 = -12

2x = -18

x = -18/2 = -9

Solution:

x = -9

y = 2

8 0
3 years ago
Please help me with this.
Marta_Voda [28]

Answer:

your answer would be c because for the team's average yardage per quarter it can't be negative!

Step-by-step explanation:

C. -56÷(-4)= 14

Mark me brainlest!!

I've done this before.

8 0
3 years ago
3 is 12% of please help asap
Korvikt [17]

Answer:

25%

Step-by-step explanation:

hopes this helps you

8 0
2 years ago
Read 2 more answers
What is the period of the function f(x) shown in the graph? Enter your answer in the box.
muminat

Answer:

Step-by-step explanation:

π

4 0
3 years ago
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