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Sphinxa [80]
3 years ago
13

Samantha earns $8 per hour at a candy store. She receives a 5% raise. What are her new hourly earnings?

Mathematics
1 answer:
d1i1m1o1n [39]3 years ago
4 0
$8 x 5 = 40

40/100 = 0.4

$8 + 0.4 = $8.4

Therefore Samantha now earns $8.4 per hour.
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Write the equation x2+24x+60=0 in the form (x+p)2=q
navik [9.2K]

Answer:

(x+12)^2=84

Step-by-step explanation:

x^2+24x+60=0

x^2+24x=-60

x^2+24x+(24/2)^2=-60+(24/2)^2

(x+24/2)^2=84

(x+12)^2=84 (ans)

4 0
2 years ago
Which statement best explains the relationship between
-Dominant- [34]

Answer: They are not perpendicular because their slopes are  not negative reciprocals.

Step-by-step explanation:

For these two lines to be perpendicular, their slopes have to be negative reciprocals.

Slope of FG.

F = (-4, 1)

G = (0, -2)

= (Y₂ - Y₁) / (X₂ - X₁)

= (-2 - 1) / (0 + 4)

= -3/4

Slope of HJ

J = (0 , 4)

H = (-4, -2)

Slope =  (Y₂ - Y₁) / (X₂ - X₁)

= (-2 - 4) / (-4 -0)

= 6/4

= 3/2

<em>The slopes of these lines are not negative reciprocals so these lines are not perpendicular. </em>

4 0
3 years ago
Write the polynomial in standard form. <br> 5z + 2z^3 - z^2 + 3z^4
pochemuha

Answer:

the standard form of this equation will be 3z^4 + 2z^3 - z^2 + 5z

Step-by-step explanation:

as much as I would like to, I'm really not that good at explaining things

5 0
3 years ago
Express the integral as a limit of Riemann sums. Do not evaluate the limit. (Use the right endpoints of each subinterval as your
Veronika [31]

The expression of integral as a limit of Riemann sums of given integral \int\limits^5_b {1} \, x/(2+x^{3}) dxis 4 \lim_{n \to \infty}∑n(n+4i)/2n^{3}+(n+4i)^{3} from i=1 to i=n.

Given an integral \int\limits^5_b {1} \, x/(2+x^{3}) dx.

We are required to express the integral as a limit of Riemann sums.

An integral basically assigns numbers to functions in a way that describes displacement, area, volume, and other concepts that arise by combining infinite data.

A Riemann sum is basically a certain kind of approximation of an integral by a finite sum.

Using Riemann sums, we have :

\int\limits^b_a {f(x)} \, dx=\lim_{n \to \infty}∑f(a+iΔx)Δx ,here Δx=(b-a)/n

\int\limits^5_1 {x/(2+x^{3}) } \, dx=f(x)=x/2+x^{3}

⇒Δx=(5-1)/n=4/n

f(a+iΔx)=f(1+4i/n)

f(1+4i/n)=[n^{2}(n+4i)]/2n^{3}+(n+4i)^{3}

\lim_{n \to \infty}∑f(a+iΔx)Δx=

\lim_{n \to \infty}∑n^{2}(n+4i)/2n^{3}+(n+4i)^{3}4/n

=4\lim_{n \to \infty}∑n(n+4i)/2n^{3}+(n+4i)^{3}

Hence the expression of integral as a limit of Riemann sums of given integral \int\limits^5_b {1} \, x/(2+x^{3}) dxis 4 \lim_{n \to \infty}∑n(n+4i)/2n^{3}+(n+4i)^{3} from i=1 to i=n.

Learn more about integral at brainly.com/question/27419605

#SPJ4

5 0
1 year ago
Please help I will reward Brainly
grigory [225]
V=(4/3)(pi)(r^3)
r=7
Hope this’ll help

7 0
3 years ago
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