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8090 [49]
3 years ago
11

One highlighter has a mass of 11 grams. Another highlighter has a mass of 10.800 milligrams. Which highlighter has the greatest

mass?
Mathematics
1 answer:
Citrus2011 [14]3 years ago
4 0
The highlighter that is 11 grams has a greater mass
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Pleaseeee help!!!! I will mark you as brainlinest for correct answer!!!!!!!!
Anni [7]
I used a graphing calculator for this.

The solution my calculator got was:

(-2.625, 0.688) My calculator is very accurate, I don't think the test expects it to be like that.

Let's find the closest coordinates.

"B" is the closest.

I hope this helps!
~kaikers
5 0
3 years ago
True or False?
neonofarm [45]
FALSE!\\The\ segments\ below\ couldn't\ form\ a\ triangle.\\\\a,b,c-lengths\ sides\ of\ a\ triangle,\ then:\\\\a+b > c\\a+c > b\\b+c > c\\\\Here:a=9;\ b=4;\ c=15\\\\a+b=9+4=13 < 15!!!!
7 0
3 years ago
Write an expression for the sequence of operations described below. multiply 3 by t, triple the result, then raise what you have
Nadusha1986 [10]

Answer: 43046721(t^8)

Step-by-step explanation:

So first, multiply 3 by t to get 3t. Then, multiply it again by 3 to get 9t. Raise it to the 8th power to get (9^8)(t^8). This gives you 43046721(t^8)

4 0
3 years ago
Please help!! Is it possible to prove that the triangles are congruent by using the AAS Congruence Theorem?
goldenfox [79]

Answer:

no, there is not enough information to use AAS congruence theorem to prove the triangles are congruent

6 0
3 years ago
For what values of k the relation R:{(k2 , 5), (3k, 6)} is not a function?
Nastasia [14]

Answer:

k=0 and k=3.

Step-by-step explanation:

To this relation be a function, the horizontal coordinates can't be equal. So, let's find the value of k that makes those coordinates equal.

k^{2}=3k\\ k^{2}-3k=0\\k(k-3)=0\\

Using the null factor property, we have

k=0\\k-3=0 \implies k=3

Therefore, the given relation is not a function when k=0 and k=3.

7 0
3 years ago
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