Correct answer is: distance from D to AB is 6cm
Solution:-
Let us assume E is the altitude drawn from D to AB.
Given that m∠ACB=120° and ABC is isosceles which means
m∠ABC=m∠BAC = 
And AC= BC
Let AC=BC=x
Then from ΔACD , cos(∠ACD) = 
Since DCB is a straight line m∠ACD+m∠ACB =180
m∠ACD = 180-m∠ACB = 60
Hence 
Now let us consider ΔBDE, sin(∠DBE) = 
Answer:
<h3>3 secs</h3>
Step-by-step explanation:
Given the height of the object as it drops from the observation deck expressed as;
h= -16t^2+152
To determine the the time it will take the object to be 8 feet above the valley floor, we will substitute h = 8 into the equation and calculate t as shown;
8 = -16t^2+152
subtract 8 from both sides
8-8 = -16t^2+152-8
0 = -16t^2+144
0-144 = -16t^2
-144 = -16t^2
16t^2 = 144
Divide both sides by 16;
16t^2/16 = 144/16
t^2 = 9
t = √9
t = 3seconds
Hence it will take 3 seconds for the object to be 8 feet above the valley floor
Answer:Two such terms are 7x^3*y^9 and -3x*y^5
Their quotient is
7x^3*y^9
--------------
-3x*y^5
This can be simplified as follows:
The numerical coefficients become -7/3.
x^3/x = x^3*x^1 = x^(3 - 1) = x^2 (we subtract the exponent of x in the denominator from the exponent of x in the numerator).
Next, y^9*y^5 = y^4.
The quotient in final reduced form is then (-7/3)x^2*y^4
Polynomial A : x^4 + 2 x³ - x² + 7 x + 11 has a Quartic degree.
Polynomial B : x² + 4 x is a Quadratic binomial.
Polynomial D : 5 x² - 2 x + 4 has a Quadratic degree.
Answer:
Polynomial D : 3 x^5 + 2 is a Quintic binomial
Answer:
f(2)=0
Step-by-step explanation:
f(2)=2x-4
2(2)-4
4-4
0
