Answer:
<h3>-700</h3>
Step-by-step explanation:

9514 1404 393
Answer:
A'(-4, -4), B'(6, -4), parallel
Step-by-step explanation:
The dilation factor multiplies each of the coordinate values. The line that was y=-2 becomes the line y=-4, a parallel horizontal line.
You did not include the problem therefore i cannot help you with this but if you could message me the problem i’d be happy too
Answer:
(2)
Step-by-step explanation:
Our logarithmic expression is:
.
Remember the logarithmic property that ln(a/b) = lna - lnb. So, we can write this as:

Also, we can write square roots as powers of one-half, so √e =
. There's another log property that:
. We can apply that here for both the √e and the y³:

Finally, note that ln(e) is just 1, so we have:

The answer is thus (2).
<em>~ an aesthetics lover</em>
Try this option:
1) if V(0;0) and x= -4, then common view of the required equiation is:
(y-k)²=4p(x-h), where focus is in (h-p;k), the vertex is in (h;k), the directrix is x=h+p, p<0 and y=k is simmetry axis;
2) if the V(0;0), then h=k=0 and the required equiation is:
y²=4px;
3) if the directrix equation is x=h+p, where h=0, then p= -4 (according to the condition the directrix equation is x= -4), then the required equation is:
y²= -16x
answer: y²= -16x