Multiplying exponents will just have to follow a rule.
Make sure that the base are the same otherwise, you keep it as is.
If they have the same bases, then just add the exponents.
= (5a^5)(6a^6)
= 30a^11
So the final answer is <span>30a^11.</span>
Answer:
c = 0.18p
Step-by-step explanation:
If you divide the number of pencils by the cost you'll get the cost of each pencil, and it's $0.18
To make y the subject, we must move everything to one side and y on the other.
Good day and I hoped that helped!
Answer:
(a): y increases on average by 8.63/unit of x1 in the first equation and increases on average by 9.01/unit of x1 in the second
(b): Yes
Step-by-step explanation:
Given
Solving (a): An interpretation of x1 coefficient
We have the coefficients of x1 to be 8.63 and 9.01
Literally, the coefficient represents the average change of y-variable per unit increase of the dependent variable
Since the coefficients of x1 in both equations are positive, then that represents an increment on the y variable.
So, the interpretation is:
y increases on average by 8.63/unit of x1 in the first equation and increases on average by 9.01/unit of x1 in the second
Solving (b): Multicollinearity
This could be the cause because x1 and x2 are related and as a result, x2 could take a part of the coefficient of x2
Answer:
The best conclusion that can be made based on the data on the dot plot is:
The mean difference is not significant because the re-randomization show that it is within the range of what could happen by chance.
Step-by-step explanation:
Randomization is the standard used to compare the observational study and balance the factors between the treatment groups and eliminate the variables' influence. Some studies analyze that the treatment in the randomization calculates the appropriate number of the subjects as the treatment to memorize is 8.9, and the treatment for the B is 12.1 words.
The mean difference is not significant because the re-randomization shows that it is within the range of what could happen by chance.
The treatment group using technique A reported a mean of 8.9 words.
The treatment group using technique B reported a mean of 12.1 words.
After the data are re-randomized, the differences of means are shown in the dot plot.
The result is significant because the re-randomization show that it is outside the range. The best conclusion that can be made based on the data on the dot plot is:
The mean difference is not significant because the re-randomization show that it is within the range of what could happen by chance.
