Let
One Number = x
Second Number =x-10
Third Number=x/2
Sum of three numbers is 50
x+x-10+x/2=50
2x-10+x/2=50
Multiply by 2 both sides
2*(2x-10+x/2)=50*2
4x-20+x=100
5x=100+20
5x=120
x=120/5
x=24
One number = x=24
Second number =x-10=24-10=14
Third number= x/2=24/2= 12
I earned 5 for x and 12 for y but I'm not sure about the «y»
2x⁴+17x²+8
Let X = x² →→(x = + or -√X )
The quadratic becomes : 2.X² + 17.X + 8. Now solve for X:
X' = [-b+√(b²-4ac)]/2a and X" = [-b-√(b²-4ac)]/2a
Plug I the values of a, b and c and you will find;
X' = -1/2 and X" = - 8
Since X = √x → →X' = √( -1/2) [imaginary roots]
and X" = √-8 →→ X" = 2√-2 [imaginary roots]
Then:
1st ROOT: X' = - √1/2.i
2nd ROOT: X" = + √1/2.i
3rd ROOT: X" = + 2√2.i
4th ROOT: X" = - 2√2.i
6.4n^2 is correct. math papa helps
Answer:
The number of adults attended was 600
Step-by-step explanation:
Let
x ----> the number of children attended
y ----> the number of adults attended
we know that
-----> equation A
----> equation B
Solve the system by graphing
The solution of the system of equations is the intersection point both graphs
using a graphing tool
The solution is the point (200,600)
see the attached figure
therefore
The number of children attended was 200 and the number of adults attended was 600
