What is the probability of rolling 2 standard dice which sum to 9?

Setler [38]

£1.00= 100 cents, 100- 64 = 36.

36

6 0

3 years ago

An arrow is shot straight up from a cliff 58.8 meters above the ground with an initial velocity of 49 meters per second. Let up

Papessa [141]

Answer:

$s(t)=-9.8t^2+49t+58.8$

Step-by-step explanation:

We have been given that an arrow is shot straight up from a cliff 58.8 meters above the ground with an initial velocity of 49 meters per second. Let up be the positive direction. Because gravity is the force pulling the arrow down, the initial acceleration of the arrow is −9.8 meters per second squared.

We know that equation of an object's height t seconds after the launch is in form $s(t)=-gt^2+v_0t+h_0$ , where

g = Force of gravity,

$v_0$ = Initial velocity,

$h_0$ = Initial height.

For our given scenario $g=-9.8$ , $v_0=49$ and $h_0=58.8$ . Upon substituting these values in object's height function, we will get:

$s(t)=-9.8t^2+49t+58.8$

Therefore, the function for the height of the arrow would be $s(t)=-9.8t^2+49t+58.8$ .

6 0

3 years ago

Differentiate y=x⁴(1-2x⁵)⁶(5-8x³)².

Liula [17]

Step-by-step explanation:

Let $y(x)=f(x)g(x)h(x)$ where

$f(x) = x^4$

$g(x)= (1 -2x^5)^6$

$h(x)= (5 - 8x^3)^2$

so that

$y(x) = x^4(1 -2x^5)^6(5 - 8x^3)^2$

Recall that the derivative of the product of functions is

$y'(x)=f'(x)g(x)h(x)+f(x)g'(x)h(x)+f(x)g(x)h'(x)$

so taking the derivatives of the individual functions, we get

$f'(x) = 4x^3$

$g'(x) = 6(1 - 2x^5)^5(-10x^4)$

$h'(x) = 2(5 - 8x^3)(-24x^2)$

So the derivative of y(x) is given by

$y'(x) = 4x^3(1 -2x^5)^6(5 - 8x^3)^2 + x^4 6(1 -2x^5)^5(-10x^4)(5 - 8x^3)^2 + x^4(1 -2x^5)^6 2(5 - 8x^3)(-24x^2)$

or

$y'(x) = 4x^3(1 -2x^5)^6(5 - 8x^3)^2$

$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:- 60x^8(1 -2x^5)^5(5 - 8x^3)^2$

$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:- 48x^6(1 -2x^5)^6 2(5 - 8x^3)$

3 0

2 years ago

Can someone help me with this??<br><br> thanks

viva [34]

Number of tickets: T.
Number of customers: c
Initially the number of tickets is T0=150, when the group hasn't sold any tickets (c=0). Then the graph must begin with c=0 and T=150. Point=(0,150). Possible options: Graph above to the right and graph below to the left.
They sell the tickets in pack of three tickets per customer c, then each time they sell a pack of three tickets to a customer, the number of tickets is reduced by 3 (-3c). Then the number of tickets, T, the group has left after selling tickets to c customers is:
T=150-3c→T=-3c+150

For T=0→-3c+150=0→150=3c→150/3=c→c=50. The graph must finish with c=50, T=0. Final point=(c,T)=(50,0)

Answer:
The correct graph is above to the right, beginning on vertical axis with T=150 and finishing on horizontal axis with c=50.
The correct equation is T=-3c+150

7 0

3 years ago

Read 2 more answers

Which expression is less than 3? 3 x 4/4, 3 x 15/8, 3 x 4/9, 3 x 1 1/8

pav-90 [236]

Answer:

3 × 4/9

Step-by-step explanation:

Remember that 4/4 is equal to 1, so 3 × 4/4 = 3

15 is bigger than 8, so we know that 15/8 is equal to 1 point something, you can find out the answer by a simple division, once you know the answer (1.875), you multiply it by 3, and get 5.625, this is larger than 3 so it is not the answer.

4 is smaller than 9, so we know that 4/9 is equal to 0 point something, again, we divide and get 0.444..., now we know that multypling something by 0 pint something is almost the same as dividing, so we can that this result is less than 3 (its 1.333).

1 and 1/8 is a mixed fraction so we know it is larger than 1, meaning that if we multiply it by 3, we will get a number larger than 3 (3.375)

8 0

2 years ago