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Verizon [17]
3 years ago
6

Y=x-3 asp need it willl make brainless

Mathematics
1 answer:
Mnenie [13.5K]3 years ago
6 0

Answer:

Line passing through (3,0)\ and\ (0,-3).

Graph is attached.

Step-by-step explanation:

y-intercept:

substitute\ x=0\\\\y=0-3\\\\y=-3\\\\Hence\ this\ line\ passes\ through\ (0,-3)

x-intercept:

Substitute\ y=0\\\\0=x-3\\\\x=3\\\\Hence\ this\ line\ passes\ through\ (3,0)

Sketch a line passing through (3,0)\ and\ (0,-3).

Graph is attached.

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What is the value of x (x+2)(x-3)=0
wolverine [178]

Answer:

x = 3 or x = -2

Step-by-step explanation:

Solve for x over the real numbers:

(x + 2) (x - 3) = 0

Hint: | Find the roots of each term in the product separately.

Split into two equations:

x - 3 = 0 or x + 2 = 0

Hint: | Look at the first equation: Solve for x.

Add 3 to both sides:

x = 3 or x + 2 = 0

Hint: | Look at the second equation: Solve for x.

Subtract 2 from both sides:

Answer: x = 3 or x = -2

8 0
3 years ago
Save Work out the size of angle AED.<br> b) Work out x
Mamont248 [21]

Answer:

x = 10°

Step-by-step explanation:

a). Since, opposite angles of a cyclic quadrilateral are supplementary angles"

   Therefore, in cyclic quadrilateral ABDE,

   m∠ABD + m∠AED = 180°

   110° + m∠AED = 180°

   m∠AED = 180° - 110°

                 = 70°

b). AD = ED [Given]

   m∠EAD = m∠AED [Since, opposite angles of equal sides are equal in measure]

   m∠EAD = m∠AED = 70°

   By triangle sum theorem in ΔABD,

   m∠BAD + m∠ABD + m∠ADB = 180°

   m∠BAD + 110° + 40° = 180°

   m∠BAD = 180 - 150

                 = 30°

    m∠AEB = m∠AED + m∠DAB [By angles addition postulate]

    m∠AEB = 70° + 30°          

                  = 100°

    By triangle sum theorem in the large triangle,

    x° + m∠AEB + m∠EAB = 180°

    x° + 100° + 70° = 180°

    x = 180 - 170

    x = 10°

8 0
2 years ago
HELP PLEASE!!! 10 PTS!!
allsm [11]

Answer:

m∠DEC = 78°

Step-by-step explanation:

Given information: AC = AD, AB⊥BD, m∠DAC = 44° and CE bisects ∠ACD.

If two sides of a triangles are congruent then the opposite angles of congruent sides are congruent.

AC = AD                 (Given)

\angle ADC\cong \angle ACD

m\angle ADC=m\angle ACD

According to the angle sum property, the sum of interior angles of a triangle is 180°.

m\angle ADC+m\angle ACD+m\angle DAC=180

m\angle ACD+m\angle ACD+44=180

2m\angle ACD=180-44

2m\angle ACD=136

Divide both sides by 2.

m\angle ACD=68

CE bisects ∠ACD.

m\angle ACE=m\angle DCE=\dfrac{\angle ACD}{2}

m\angle ACE=m\angle DCE=\dfrac{68}{2}

m\angle ACE=m\angle DCE=34

Use angle sum property in triangle CDE,

m\angle CDE+m\angle DCE+m\angle DEC=180

68+34+m\angle DEC=180

68+34+m\angle DEC=180

102+m\angle DEC=180

Subtract 102 from both sides.

m\angle DEC=180-102

m\angle DEC=78

Therefore, the measure of angle DEC is 78°.

6 0
3 years ago
I need help on Dividing Fractions?
vlabodo [156]

You have to write the problem you need help with.
7 0
3 years ago
Read 2 more answers
Simplify the fraction 6/12 by dividing top &amp; bottom numbers by the GCF
ipn [44]
6/12 is 1/2 the GCF is 6
5 0
4 years ago
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