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Mathematics

1 answer:

strojnjashka [21]3 years ago

7 0

$\implies {\blue {\boxed {\boxed {\purple {\sf {D. \: {9}^{2} }}}}}}$

$\large\mathfrak{{\pmb{\underline{\red{Step-by-step\:explanation}}{\red{:}}}}}$

${9}^{5} \div {9}^{3}$

➼ $\: {9}^{5 - 3}$

➼ $\: {9}^{2}$

${a}^{m} \div {a}^{n} = {a}^{m - n}$

$\large\mathfrak{{\pmb{\underline{\orange{Mystique35 }}{\orange{❦}}}}}$

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<h2><em>29.4 length and 21.4 width.</em></h2>

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To fin the dimensions of the pool we need to use the total area of the pool plus the concrete walkway. Lets say that <em>W </em>is the width and <em>L </em>the length. We know that, the walkway has 3 ft wide, this means that the width and length are increased by 6ft (3ft on each side). So, the total area can be expressed like this: $A_{total} = (L+6)(W+6)$ .

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$A_{total} = (L+6)(W+6)\\970 = (W+8+6)(W+6)\\970=W^{2}+20W+84\\W^{2}+20W-886=0$

With this quadratic equation we're gonna have to solution, the most reasonable is part of the answer. So, solving the equation we have as solutions: $W_{1}=21.4$ and $W_{2}=-41.4$