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Ad libitum [116K]
3 years ago
5

The box plot represents the amount of time 15 pet owners spend exercising their pets each day.

Mathematics
1 answer:
Blizzard [7]3 years ago
4 0
Right around 75 I would believe
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What equation has a solution of 2/3 for x
Ahat [919]

Answer:

D

Step-by-step explanation:

Hope this helped! Please tell me if I'm wrong!

6 0
3 years ago
Help plssss I’m trying to finish this diagnostics test
Allushta [10]

Answer: 5 Seconds

Step-by-step explanation: Given the equation of the height expressed ad;

h(t) = - 16t^2 + initial height

Given that initial height = 400feet

h(t) = - 16t^2 + 400

The waste will hit the ground at when h(t) = 0

substitute

0 =  - 16t^2 + 400

16t^2 = 400

t² = 400/16

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4 0
3 years ago
Pls help me with A, B, C
Mariulka [41]

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Step-by-step explanation:

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6 0
3 years ago
A quantity b varies jointly with c and d and inversely with eWhen b is 18, c is 4, d is 9, and e is 6What is the constant of var
777dan777 [17]

Answer:

constant of variation = 3

Step-by-step explanation:

we know that b varies jointly with c and d

so:

b∝c∝d

and b varies inversely with e, so

b∝\frac{1}{e}

and i will call the constant of variation k, this way we can make an equation for b in the following form:

b=k\frac{cd}{e}

this satisfy that b varies jointly with c and d (if b increases, c and d also increase) and inversely with e (if b increases, e decreases)

we know that when b is 18, c is 4, d is 9, and e is 6:

b=18\\c=4\\d=9\\e=6

substituting this in our equation for b:

b=k\frac{cd}{e}\\ 18=k\frac{(4)(9)}{6}

and we solve operations and clear for the constant of variation k:

18=k\frac{36}{6}\\ 18=6k\\\frac{18}{6}=k\\ 3=k

the constant of variation is 3.

4 0
3 years ago
Read 2 more answers
Solve for x <br> help ASAP
puteri [66]

Answer: x=6 and the angle is 50

Step-by-step explanation:

1. a whole triangle = 180°

2. subtract 70 and 60 to get 50

3. subtract 2 from 50 and get 48

4. divide 48 by 8 and you get 6.

hope this helps :) everyone reading this have a great day!

7 0
3 years ago
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