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11111nata11111 [884]
3 years ago
5

Find the distance snd midpoint between points (-9,-4) and (-4,-10)

Mathematics
1 answer:
Airida [17]3 years ago
3 0
A (-9-4)
B (-4-10)
Distance between two points:
\sqrt{(xb - xa) {}^{2} + (yb - ya) {}^{2}  }
\sqrt{( - 4 + 9) {}^{2}  + ( - 10 + 4) {}^{2} }
\sqrt{5 {}^{2}  + ( - 6) {}^{2} }
\sqrt{25 + 36}
\sqrt{61}
7.8
Midpoint coordinates (xa+xb/2, ya+yb/2)
(-9-4/2, -4-10/2)
(-13/2, -14/2)
(-13/2, -7)
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11x-y or 5x+y.

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If all 108 people take 2 biscuits, how many biscuits will you need?
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PLEASEEEEEEEEEEEEEEEEEE URGENT
jeyben [28]

Option C:

f(x) = 5x + 7 is the function of the input-output table.

Solution:

Option A: f(x) = 6x + 9

Input x = 1 in the above equation.

f(1) = 6(1) + 9

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f(1) = 15

But the output is 12 in the table.

So, it is not the function of the table.

Option B: f(x) = 7x + 5

Input x = 1 in the above equation.

f(1) = 7(1) + 5

f(1) = 12

Input x = 5 in the above equation.

f(5) = 7(5) + 5

f(5) = 40

But the output is 32 in the table.

So, it is not the function of the table.

Option C: f(x) = 5x + 7

Input x = 1 in the above equation.

f(1) = 5(1) + 7

f(1) = 12

Input x = 5 in the above equation.

f(5) = 5(5) + 7

f(5) = 32

Input x = 10 in the above equation.

f(10) = 5(10) + 7

f(10) = 57

Input x = 5 in the above equation.

f(15) = 5(15) + 7

f(15) = 82

All outputs are correct for the given input.

Hence it is the function of the table.

Option D: f(x) = 12x + 1

Input x = 1 in the above equation.

f(1) = 12(1) + 1

f(1) = 12

Input x = 5 in the above equation.

f(5) = 12(5) + 1

f(5) = 61

But the output is 32 in the table.

So, it is not the function of the table.

Hence Option C is the correct answer.

f(x) = 5x + 7 is the function of the input-output table.

4 0
3 years ago
Find b. Question 19 options:<br><br><br>70.1<br><br><br>57.7<br><br><br>31.5<br><br><br>43.8
Reptile [31]

Answer: 57.7

Step-by-step explanation:

6 0
3 years ago
Solve the following system using substitution
julsineya [31]
Change x+y=5 to y=5-x
x+5-x=-3
0=-8
The answer is no solution. :)
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