Answer:
The area of triangle is 
Step-by-step explanation:
we know that
The area of a triangle is equal to
A=(1/2)bh
we have
b=8 1/3 m
convert to an improper fraction
8 1/3 m=(8*3+1)/3=25/3 m
The fourth root of 16 is equal to 2
![\sqrt[4]{16}=(2^{4})^{1/4}=2](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7B16%7D%3D%282%5E%7B4%7D%29%5E%7B1%2F4%7D%3D2)
so
h=2 m
substitute
convert to mixed number
The answer is (1/2)xe^(2x) - (1/4)e^(2x) + C
Solution:
Since our given integrand is the product of the functions x and e^(2x), we can use the formula for integration by parts by choosing
u = x
dv/dx = e^(2x)
By differentiating u, we get
du/dx= 1
By integrating dv/dx= e^(2x), we have
v =∫e^(2x) dx = (1/2)e^(2x)
Then we substitute these values to the integration by parts formula:
∫ u(dv/dx) dx = uv −∫ v(du/dx) dx
∫ x e^(2x) dx = (x) (1/2)e^(2x) - ∫ ((1/2) e^(2x)) (1) dx
= (1/2)xe^(2x) - (1/2)∫[e^(2x)] dx
= (1/2)xe^(2x) - (1/2) (1/2)e^(2x) + C
where c is the constant of integration.
Therefore,
∫ x e^(2x) dx = (1/2)xe^(2x) - (1/4)e^(2x) + C
Answer:
2
Step-by-step explanation:
the mode is the one that appears the most, most common one
Answer:
y=sqrt((x+a)/-2b))
F=(5/9)C+32
Can't read the rest
Step-by-step explanation:
-2by^2=x+a
y^2=(x+a)/-2b
y=sqrt((x+a)/-2b))
F-32=(5/9)C
F=(5/9)C+32 (The actual Fahrenheit-Celcius formula)
NOTE: The other pictures cannot be opened.
